Solution 3.1:2e
From Förberedande kurs i matematik 1
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| - | Looking first at   | + | Looking first at <math>\sqrt{18}</math> this square root expression can be simplified by writing 18 as a product of its smallest possible integer factors  | 
| - | <math>\sqrt{18}</math>  | + | |
| - | this square root expression can be simplified by writing   | + | |
| - | + | ||
| - | as a product of its smallest possible integer factors  | + | |
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| + | {{Displayed math||<math>18 = 2\cdot 9 = 2\cdot 3\cdot 3 = 2\cdot 3^{2}</math>}}  | ||
and then we can take the quadratic out of the square root sign by using the rule   | and then we can take the quadratic out of the square root sign by using the rule   | ||
| - | <math>\sqrt{a^{2}b}=a\sqrt{b}</math>,  | + | <math>\sqrt{a^{2}b}=a\sqrt{b}</math> (valid for non-negative ''a'' and ''b''),  | 
| + | {{Displayed math||<math>\sqrt{18} = \sqrt{2\cdot 3^{2}} = 3\sqrt{2}\,\textrm{.}</math>}}  | ||
| - | + | In the same way, we write <math>8 = 2\cdot 4 = 2\cdot 2\cdot 2 = 2^{3}</math> and get  | |
| - | + | ||
| - | In the same way, we write   | + | |
| - | <math>8=2\  | + | |
| - | and get  | + | |
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| - | + | ||
| - | + | ||
| + | {{Displayed math||<math>\sqrt{8} = \sqrt{2\cdot 2^{2}} = 2\sqrt{2}\,\textrm{.}</math>}}  | ||
All together, we get  | All together, we get  | ||
| - | + | {{Displayed math||<math>\begin{align}  | |
| - | <math>\begin{align}  | + | \sqrt{18}\sqrt{8}  | 
| - | + | &= 3\sqrt{2}\cdot 2\sqrt{2}\\[5pt]  | |
| - | & =3\  | + | &= 3\cdot 2\cdot \bigl(\sqrt{2}\bigr)^{2}\\[5pt]   | 
| - | &   | + | &= 3\cdot 2\cdot 2\\[5pt]  | 
| - | \end{align}</math>  | + | &= 12\,\textrm{.}  | 
| + | \end{align}</math>}}  | ||
Current revision
Looking first at \displaystyle \sqrt{18} this square root expression can be simplified by writing 18 as a product of its smallest possible integer factors
| \displaystyle 18 = 2\cdot 9 = 2\cdot 3\cdot 3 = 2\cdot 3^{2} | 
and then we can take the quadratic out of the square root sign by using the rule \displaystyle \sqrt{a^{2}b}=a\sqrt{b} (valid for non-negative a and b),
| \displaystyle \sqrt{18} = \sqrt{2\cdot 3^{2}} = 3\sqrt{2}\,\textrm{.} | 
In the same way, we write \displaystyle 8 = 2\cdot 4 = 2\cdot 2\cdot 2 = 2^{3} and get
| \displaystyle \sqrt{8} = \sqrt{2\cdot 2^{2}} = 2\sqrt{2}\,\textrm{.} | 
All together, we get
| \displaystyle \begin{align}
 \sqrt{18}\sqrt{8} &= 3\sqrt{2}\cdot 2\sqrt{2}\\[5pt] &= 3\cdot 2\cdot \bigl(\sqrt{2}\bigr)^{2}\\[5pt] &= 3\cdot 2\cdot 2\\[5pt] &= 12\,\textrm{.} \end{align}  | 
