Solution 2.3:5a
From Förberedande kurs i matematik 1
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In this exercise we can use the technique for writing equations in factorized form. Consider in our case the equation  | In this exercise we can use the technique for writing equations in factorized form. Consider in our case the equation  | ||
| + | {{Displayed math||<math>(x+7)(x+7)=0\,\textrm{.}</math>}}  | ||
| - | <math>  | + | This equation has only <math>x=-7</math> as a root because both factors become zero only when <math>x=-7</math>. In addition, it is an second-degree equation, which we can clearly see if the left-hand side is expanded,  | 
| - | + | {{Displayed math||<math>(x+7)(x+7) = x^{2}+14x+49\,\textrm{.}</math>}}  | |
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| - | <math>x=  | + | |
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| + | Thus, one answer is the equation <math>x^{2}+14x+49=0\,</math>.  | ||
| - | <math>\left( x+7 \right)\left( x+7 \right)=x^{2}+14x+49</math>  | ||
| + | Note: All second-degree equations which have <math>x=-7</math> as its sole root can be written as  | ||
| - | + | {{Displayed math||<math>ax^{2}+14ax+49a=0\,,</math>}}  | |
| - | <math>  | + | |
| - | + | where ''a'' is a non-zero constant.  | |
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| - | where   | + | |
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| - | is a non-zero constant.  | + | |
Current revision
In this exercise we can use the technique for writing equations in factorized form. Consider in our case the equation
| \displaystyle (x+7)(x+7)=0\,\textrm{.} | 
This equation has only \displaystyle x=-7 as a root because both factors become zero only when \displaystyle x=-7. In addition, it is an second-degree equation, which we can clearly see if the left-hand side is expanded,
| \displaystyle (x+7)(x+7) = x^{2}+14x+49\,\textrm{.} | 
Thus, one answer is the equation \displaystyle x^{2}+14x+49=0\,.
Note: All second-degree equations which have \displaystyle x=-7 as its sole root can be written as
| \displaystyle ax^{2}+14ax+49a=0\,, | 
where a is a non-zero constant.
