Solution 3.1:1c

From Förberedande kurs i matematik 1

(Difference between revisions)
Jump to: navigation, search
Line 1: Line 1:
 +
<math>\sqrt[3]{3}</math>
<math>\sqrt[3]{3}</math>
means
means
-
<math>\text{3}^{\text{1}/\text{3}}~</math>
+
<math>3^{1/3}~</math>
and then
and then
<math>\left( \sqrt[3]{3} \right)^{4}=\left( 3^{{1}/{3}\;} \right)^{4}=3^{\frac{1}{3}\centerdot 4}=3^{\frac{4}{3}}</math>
<math>\left( \sqrt[3]{3} \right)^{4}=\left( 3^{{1}/{3}\;} \right)^{4}=3^{\frac{1}{3}\centerdot 4}=3^{\frac{4}{3}}</math>

Revision as of 10:11, 22 September 2008

\displaystyle \sqrt[3]{3} means \displaystyle 3^{1/3}~ and then


\displaystyle \left( \sqrt[3]{3} \right)^{4}=\left( 3^{{1}/{3}\;} \right)^{4}=3^{\frac{1}{3}\centerdot 4}=3^{\frac{4}{3}}

Retrieved from "http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-ImperialCollege/index.php/Solution_3.1:1c"