Answer 5.1:6
From Förberedande kurs i matematik 1
(Difference between revisions)
(New page: {| width="100%" cellspacing="10px" |a) |width="100%" | \ln(4\times 3)=\ln 4+\ln 3 |- |b) |width="100%" | \ln(4-3)\ne \ln 4-\ln 3 |- |c) |width="100%" | \log_{2}4 = \dfrac{\ln 4}{\ln 2} |- ...) |
(New page: {| width="100%" cellspacing="10px" |a) |width="100%" | \ln(4\times 3)=\ln 4+\ln 3 |- |b) |width="100%" | \ln(4-3)\ne \ln 4-\ln 3 |- |c) |width="100%" | \log_{2}4 = \dfrac{\ln 4}{\ln 2} |- ...) |
Current revision
| a) | \ln(4\times 3)=\ln 4+\ln 3 |
| b) | \ln(4-3)\ne \ln 4-\ln 3 |
| c) | \log_{2}4 = \dfrac{\ln 4}{\ln 2} |
| d) | 2^{\log_{2}4} = 4 |
