5. Exercises
From Förberedande kurs i matematik 1
(Difference between revisions)
Line 10: | Line 10: | ||
===Exercise 5:1=== | ===Exercise 5:1=== | ||
<div class="ovning"> | <div class="ovning"> | ||
- | + | Write the formulas in TeX | |
{| width="100%" cellspacing="10px" | {| width="100%" cellspacing="10px" | ||
|a) | |a) | ||
- | |width="50%" | <math> | + | |width="50%" | <math>\displaystyle\frac{a+b}{d-c}</math> |
|b) | |b) | ||
- | |width="50%" | <math>3 | + | |width="50%" | <math>\sqrt{3}</math> |
|- | |- | ||
|c) | |c) | ||
- | || <math> | + | || <math>4x^2 - x</math> |
|d) | |d) | ||
- | || <math> | + | || <math>\sin^2 x + \cos x</math> |
|} | |} | ||
- | </div>{{#NAVCONTENT:Answer|Answer 5.1:1 | + | </div>{{#NAVCONTENT:Answer|Answer 5.1:1}} |
Revision as of 15:05, 20 January 2009
Theory | Exercises |
Exercise 5:1
Write the formulas in TeX
a) | \displaystyle \displaystyle\frac{a+b}{d-c} | b) | \displaystyle \sqrt{3} |
c) | \displaystyle 4x^2 - x | d) | \displaystyle \sin^2 x + \cos x |
Answer
Exercise 5:2
Simplify
a) | \displaystyle (3-(7-4))(6-5) | b) | \displaystyle 3-(((7-4)+6)-5) |
c) | \displaystyle 3\cdot(-7)-4\cdot(6-5) | d) | \displaystyle 3\cdot(-7)-(4+6)/(-5) |
Answer
Solution a
Solution b
Solution c
Solution d