Solution 4.1:3a
From Förberedande kurs i matematik 1
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| - | {{  | + | A right-angled triangle is a triangle in which one of the angles is   | 
| - | <  | + | <math>90^{\circ }</math>. The side which is opposite the   | 
| - | {{  | + | <math>90^{\circ }</math>  | 
| + | -angle is called the hypotenuse (marked   | ||
| + | <math>x</math>  | ||
| + | in the triangle) and the others are called opposite and the adjacent.  | ||
| + | |||
| + | With the help of Pythagoras' theorem, we can write a relation between the sides of a right  | ||
| + | angled triangle:  | ||
| + | |||
| + | |||
| + | <math>x^{2}=30^{2}+40^{2}</math>  | ||
| + | |||
| + | |||
| + | This equation gives us that  | ||
| + | |||
| + | |||
| + | <math>\begin{align}  | ||
| + | & x=\sqrt{30^{2}+40^{2}}=\sqrt{900+1600}=\sqrt{2500} \\   | ||
| + | & =\sqrt{25\centerdot 100}=\sqrt{5^{2}\centerdot 10^{2}}=5\centerdot 10=50 \\   | ||
| + | \end{align}</math>  | ||
Revision as of 09:26, 27 September 2008
A right-angled triangle is a triangle in which one of the angles is \displaystyle 90^{\circ }. The side which is opposite the \displaystyle 90^{\circ } -angle is called the hypotenuse (marked \displaystyle x in the triangle) and the others are called opposite and the adjacent.
With the help of Pythagoras' theorem, we can write a relation between the sides of a right angled triangle:
\displaystyle x^{2}=30^{2}+40^{2}
This equation gives us that
\displaystyle \begin{align}
& x=\sqrt{30^{2}+40^{2}}=\sqrt{900+1600}=\sqrt{2500} \\ 
& =\sqrt{25\centerdot 100}=\sqrt{5^{2}\centerdot 10^{2}}=5\centerdot 10=50 \\ 
\end{align}
