Solution 3.3:2e

From Förberedande kurs i matematik 1

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From the definition of logarithm base
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<math>\text{1}0</math>, we see directly that
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<math>\text{1}0^{\text{lg}\,\text{2}}=\text{2}</math>.

Revision as of 13:16, 25 September 2008

From the definition of logarithm base \displaystyle \text{1}0, we see directly that \displaystyle \text{1}0^{\text{lg}\,\text{2}}=\text{2}.

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