From Förberedande kurs i matematik 1

Revision as of 09:26, 9 September 2008 (edit) Tekbot (Talk | contribs) m (Lösning 3.3:4b moved to Solution 3.3:4b: Robot: moved page) ← Previous diff		Current revision (07:09, 2 October 2008) (edit) (undo) Tek (Talk | contribs) m
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-	{{NAVCONTENT_START}}	+	The two terms can be combined into one logarithmic expression using the log law
-	<center> [[Image:3_3_4b.gif]] </center>	+	<math>\lg a + \lg b = \lg (ab)</math>,
-	{{NAVCONTENT_STOP}}	+
		+	{{Displayed math||<math>\lg 23 + \lg\frac{1}{23} = \lg \Bigl(23\cdot\frac{1}{23}\Bigr) = \lg 1 = 0\,\textrm{.}</math>}}

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Current revision

The two terms can be combined into one logarithmic expression using the log law \displaystyle \lg a + \lg b = \lg (ab),

\displaystyle \lg 23 + \lg\frac{1}{23} = \lg \Bigl(23\cdot\frac{1}{23}\Bigr) = \lg 1 = 0\,\textrm{.}