From Förberedande kurs i matematik 1

Revision as of 09:26, 9 September 2008 (edit) Tekbot (Talk | contribs) m (Lösning 3.3:4a moved to Solution 3.3:4a: Robot: moved page) ← Previous diff		Current revision (07:07, 2 October 2008) (edit) (undo) Tek (Talk | contribs) m
(One intermediate revision not shown.)
Line 1:		Line 1:
-	{{NAVCONTENT_START}}	+	Individually, the terms are difficult to calculate, but the two logarithms can be lumped together using the logarithm law, <math>\log a - \log b = \log\frac{a}{b}\,</math>,
-	<center> [[Image:3_3_4a.gif]] </center>	+
-	{{NAVCONTENT_STOP}}	+	{{Displayed math||<math>\lg 50 - \lg 5 = \lg\frac{50}{5} = \lg 10 = 1\,\textrm{.}</math>}}

---

Current revision

Individually, the terms are difficult to calculate, but the two logarithms can be lumped together using the logarithm law, \displaystyle \log a - \log b = \log\frac{a}{b}\,,

\displaystyle \lg 50 - \lg 5 = \lg\frac{50}{5} = \lg 10 = 1\,\textrm{.}