From Förberedande kurs i matematik 1

Revision as of 09:50, 26 March 2008 (edit) Lina (Talk | contribs) (Ny sida: {{NAVCONTENT_START}} <center> Bild:1_2_1e.gif </center> {{NAVCONTENT_STOP}}) ← Previous diff		Current revision (07:38, 19 September 2008) (edit) (undo) Tek (Talk | contribs) m
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-	{{NAVCONTENT_START}}	+	The first step is to expand the fractions so that they have a common denominator,
-	<center> [[Bild:1_2_1e.gif]] </center>	+
-	{{NAVCONTENT_STOP}}	+	{{Displayed math||<math>\frac{8\cdot 4\cdot 3}{7\cdot 4\cdot 3}+\frac{3\cdot 7\cdot 3}{4\cdot 7\cdot 3}-\frac{4\cdot 7\cdot 4}{3\cdot 7\cdot 4}=\frac{96}{84}+\frac{63}{84}-\frac{112}{84}\,</math>.}}
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		+	After that, the expression can be calculated by adding and subtracting the numerators
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		+	{{Displayed math||<math>\frac{96}{84}+\frac{63}{84}-\frac{112}{84}=\frac{96+63-112}{84}=\frac{47}{84}\,</math>.}}

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Current revision

The first step is to expand the fractions so that they have a common denominator,

\displaystyle \frac{8\cdot 4\cdot 3}{7\cdot 4\cdot 3}+\frac{3\cdot 7\cdot 3}{4\cdot 7\cdot 3}-\frac{4\cdot 7\cdot 4}{3\cdot 7\cdot 4}=\frac{96}{84}+\frac{63}{84}-\frac{112}{84}\,.

After that, the expression can be calculated by adding and subtracting the numerators

\displaystyle \frac{96}{84}+\frac{63}{84}-\frac{112}{84}=\frac{96+63-112}{84}=\frac{47}{84}\,.