Answer 5.1:1
From Förberedande kurs i matematik 1
(Difference between revisions)
(New page: {| width="100%" cellspacing="10px" |a) |width="50%" | \displaystyle\frac{a+b}{d-c} |b) |width="50%" | \sqrt{3} |- |c) ||4x^2 - x |d) || \sin^2 x + \cos x |}) |
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{| width="100%" cellspacing="10px" | {| width="100%" cellspacing="10px" | ||
|a) | |a) | ||
| - | |width="50%" | \displaystyle\frac{a+b}{d-c} | + | |width="50%" | <math>\displaystyle\frac{a+b}{d-c}</math> |
|b) | |b) | ||
| - | |width="50%" | \sqrt{3} | + | |width="50%" | <math>\sqrt{3}</math> |
|- | |- | ||
|c) | |c) | ||
| - | ||4x^2 - x | + | || <math>4x^2 - x</math> |
|d) | |d) | ||
| - | || \sin^2 x + \cos x | + | || <math>\sin^2 x + \cos x</math> |
|} | |} | ||
Revision as of 13:14, 22 January 2009
| a) | <math>\displaystyle\frac{a+b}{d-c}</math> | b) | <math>\sqrt{3}</math> |
| c) | <math>4x^2 - x</math> | d) | <math>\sin^2 x + \cos x</math> |
