From Förberedande kurs i matematik 1

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-	{{NAVCONTENT_START}}	+	There are two angles in the unit circle, <math>x=0</math> and <math>x=\pi</math>, whose sine has a value of zero.
-	<center> [[Bild:4_4_2c.gif]] </center>	+
-	{{NAVCONTENT_STOP}}	+
-	[[Bild:4_4_2_c.gif|center]]	+	[[Image:4_4_2_c.gif|center]]
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		+	We get the full solution when we add multiples of <math>2\pi</math>,
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		+	{{Displayed math||<math>x = 0+2n\pi\qquad\text{and}\qquad x = \pi + 2n\pi\,,</math>}}
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		+	where ''n'' is an arbitrary integer.
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		+	Note: Because the difference between <math>0</math> and <math>\pi</math> is a half turn, the solutions are repeated every half turn and they can be summarized in one expression,
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		+	{{Displayed math||<math>x=0+n\pi\,,</math>}}
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		+	where ''n'' is an arbitrary integer.

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Current revision

There are two angles in the unit circle, \displaystyle x=0 and \displaystyle x=\pi, whose sine has a value of zero.

We get the full solution when we add multiples of \displaystyle 2\pi,

\displaystyle x = 0+2n\pi\qquad\text{and}\qquad x = \pi + 2n\pi\,,

where n is an arbitrary integer.

Note: Because the difference between \displaystyle 0 and \displaystyle \pi is a half turn, the solutions are repeated every half turn and they can be summarized in one expression,

\displaystyle x=0+n\pi\,,

where n is an arbitrary integer.