Solution 4.2:2a
From Förberedande kurs i matematik 1
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- | { | + | The opposite and adjacent are given in the right-angled triangle and this means that the value of the tangent for the angle can be determined as the quotient between the opposite and the adjacent: |
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- | + | {| width="100%" | |
- | [[Image:4_2_2_a.gif | + | | width="50%" align="center"|<math>\tan v = 2/5</math> |
+ | | width="50%" align="left"|[[Image:4_2_2_a.gif]] | ||
+ | |} | ||
+ | |||
+ | At the same time, this is a trigonometric equation for the angle ''v''. | ||
+ | |||
+ | |||
+ | Note: In the chapter on "Trigonometric equations", we will investigate more closely how to solve equations of this type. |
Current revision
The opposite and adjacent are given in the right-angled triangle and this means that the value of the tangent for the angle can be determined as the quotient between the opposite and the adjacent:
\displaystyle \tan v = 2/5 | ![]() |
At the same time, this is a trigonometric equation for the angle v.
Note: In the chapter on "Trigonometric equations", we will investigate more closely how to solve equations of this type.