Solution 4.3:4c
From Förberedande kurs i matematik 1
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| - | {{ | + | The formula for double angles gives |
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| - | {{ | + | {{Displayed math||<math>\sin 2v=2\sin v\cos v</math>}} |
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| + | and from exercise b, we have <math>\sin v = \sqrt{1-b^2}\,</math>. Thus, | ||
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| + | {{Displayed math||<math>\sin 2v = 2b\sqrt{1-b^2}\,\textrm{.}</math>}} | ||
Current revision
The formula for double angles gives
| \displaystyle \sin 2v=2\sin v\cos v |
and from exercise b, we have \displaystyle \sin v = \sqrt{1-b^2}\,. Thus,
| \displaystyle \sin 2v = 2b\sqrt{1-b^2}\,\textrm{.} |
