Solution 4.3:4a

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The Pythagorean identity
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The Pythagorean identity <math>\cos^2 v + \sin^2 v = 1</math> gives us directly that
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<math>\cos ^{2}v+\sin ^{2}v=1</math>
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gives us directly that
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{{Displayed math||<math>\sin^2 v = 1-\cos^2 v = 1-b^2\,\textrm{.}</math>}}
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<math>\sin ^{2}v=1-\cos ^{2}v=1-b^{2}</math>
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Current revision

The Pythagorean identity \displaystyle \cos^2 v + \sin^2 v = 1 gives us directly that

\displaystyle \sin^2 v = 1-\cos^2 v = 1-b^2\,\textrm{.}
Retrieved from "http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-ImperialCollege/index.php/Solution_4.3:4a"