From Förberedande kurs i matematik 1

Revision as of 09:42, 9 September 2008 (edit) Tekbot (Talk | contribs) m (Lösning 4.2:2b moved to Solution 4.2:2b: Robot: moved page) ← Previous diff		Current revision (14:29, 8 October 2008) (edit) (undo) Tek (Talk | contribs) m
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-	{{NAVCONTENT_START}}	+	In this right-angled triangle, the opposite and the hypotenuse are given. This means that we can directly set up a relation for the sine of the angle ''v'',
-	<center> [[Image:4_2_2b.gif]] </center>	+
-	{{NAVCONTENT_STOP}}	+	{| width="100%"
-	[[Image:4_2_2_b.gif|center]]	+	|width="50%" align="center"|<math>\sin v = \frac{70}{110}\,\textrm{.}</math>
		+	|width="50%" align="center"|[[Image:4_2_2_b.gif]]
		+	|}
		+
		+	The right-hand side in this equation can be simplified, so that we get
		+
		+	{{Displayed math||<math>\sin v = \frac{7}{11}\,\textrm{.}</math>}}

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Current revision

In this right-angled triangle, the opposite and the hypotenuse are given. This means that we can directly set up a relation for the sine of the angle v,

\displaystyle \sin v = \frac{70}{110}\,\textrm{.}

The right-hand side in this equation can be simplified, so that we get

\displaystyle \sin v = \frac{7}{11}\,\textrm{.}