Solution 4.2:1f
From Förberedande kurs i matematik 1
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| - | + | The side adjacent to the angle of 50° is marked ''x'' and the opposite is the side of length 19.  | |
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[[Image:4_2_1_f.gif|center]]  | [[Image:4_2_1_f.gif|center]]  | ||
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| + | If we write the tangent for the angle, this gives a relation which contains ''x'' as the only unknown,  | ||
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| + | {{Displayed math||<math>\tan 50^{\circ} = \frac{19}{x}\,\textrm{.}</math>}}  | ||
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| + | This gives   | ||
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| + | {{Displayed math||<math>x=\frac{19}{\tan 50^{\circ }}\quad ({}\approx 15\textrm{.}9)\,\textrm{.}</math>}}  | ||
Current revision
The side adjacent to the angle of 50° is marked x and the opposite is the side of length 19.
If we write the tangent for the angle, this gives a relation which contains x as the only unknown,
| \displaystyle \tan 50^{\circ} = \frac{19}{x}\,\textrm{.} | 
This gives
| \displaystyle x=\frac{19}{\tan 50^{\circ }}\quad ({}\approx 15\textrm{.}9)\,\textrm{.} | 

