From Förberedande kurs i matematik 1

Revision as of 10:01, 27 September 2008 (edit) Ian (Talk | contribs) ← Previous diff		Current revision (10:30, 7 October 2008) (edit) (undo) Tek (Talk | contribs) m
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	If we use the distance formula		If we use the distance formula
		+	{{Displayed math||<math>d=\sqrt{(x-a)^2+(y-b)^2}</math>}}
-	<math>d=\sqrt{\left( x-a \right)^{2}+\left( y-b \right)^{2}}</math>	+	to determine the distance between the points <math>(x,y) = (-2,5)</math> and <math>(a,b) = (3,-1)</math>, we get
-		+	{{Displayed math||<math>\begin{align}
-	to determine the distance between the points	+	d &= \sqrt{(-2-3)^2+(5-(-1))^2}\\[5pt]
-	<math>\left( x \right.,\left. y \right)=\left( -2 \right.,\left. 5 \right)</math>	+	&= \sqrt{(-5)^2+6^2}\\[5pt]
-	and	+	&= \sqrt{25+36}\\[5pt]
-	<math>\left( a \right.,\left. b \right)=\left( 3 \right.,\left. -1 \right)</math>, we get	+	&= \sqrt{61}\,\textrm{.}
-		+	\end{align}</math>}}
-		+
-	<math>\begin{align}	+
-	& d=\sqrt{\left( -2-3 \right)^{2}+\left( 5-\left( -1 \right) \right)^{2}} \\	+
-	& =\sqrt{\left( -5 \right)^{2}+6^{2}}=\sqrt{25+36}=\sqrt{61} \\	+
-	\end{align}</math>	+

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Current revision

If we use the distance formula

\displaystyle d=\sqrt{(x-a)^2+(y-b)^2}

to determine the distance between the points \displaystyle (x,y) = (-2,5) and \displaystyle (a,b) = (3,-1), we get

\displaystyle \begin{align} d &= \sqrt{(-2-3)^2+(5-(-1))^2}\\[5pt] &= \sqrt{(-5)^2+6^2}\\[5pt] &= \sqrt{25+36}\\[5pt] &= \sqrt{61}\,\textrm{.} \end{align}