From Förberedande kurs i matematik 1

Revision as of 07:04, 21 August 2008 (edit) Tekbot (Talk | contribs) m (Robot: Automated text replacement (-[[Bild: +[[Image:)) ← Previous diff		Current revision (10:30, 7 October 2008) (edit) (undo) Tek (Talk | contribs) m
(2 intermediate revisions not shown.)
Line 1:		Line 1:
-	{{NAVCONTENT_START}}	+	If we use the distance formula
-	<center> [[Image:4_1_4b.gif]] </center>	+
-	{{NAVCONTENT_STOP}}	+	{{Displayed math||<math>d=\sqrt{(x-a)^2+(y-b)^2}</math>}}
		+
		+	to determine the distance between the points <math>(x,y) = (-2,5)</math> and <math>(a,b) = (3,-1)</math>, we get
		+
		+	{{Displayed math||<math>\begin{align}
		+	d &= \sqrt{(-2-3)^2+(5-(-1))^2}\\[5pt]
		+	&= \sqrt{(-5)^2+6^2}\\[5pt]
		+	&= \sqrt{25+36}\\[5pt]
		+	&= \sqrt{61}\,\textrm{.}
		+	\end{align}</math>}}

---

Current revision

If we use the distance formula

\displaystyle d=\sqrt{(x-a)^2+(y-b)^2}

to determine the distance between the points \displaystyle (x,y) = (-2,5) and \displaystyle (a,b) = (3,-1), we get

\displaystyle \begin{align} d &= \sqrt{(-2-3)^2+(5-(-1))^2}\\[5pt] &= \sqrt{(-5)^2+6^2}\\[5pt] &= \sqrt{25+36}\\[5pt] &= \sqrt{61}\,\textrm{.} \end{align}