Solution 4.1:3a
From Förberedande kurs i matematik 1
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| - | {{  | + | A right-angled triangle is a triangle in which one of the angles is 90°. The side which is opposite the 90°-angle is called the hypotenuse (marked ''x'' in the triangle) and the others are called opposite and the adjacent.  | 
| - | <  | + | |
| - | {{  | + | With the help of the Pythagorean theorem, we can write a relation between the sides of a right-angled triangle  | 
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| + | {{Displayed math||<math>x^2 = 30^2 + 40^2\,\textrm{.}</math>}}  | ||
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| + | This equation gives us that  | ||
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| + | {{Displayed math||<math>\begin{align}  | ||
| + | x &= \sqrt{30^{2}+40^{2}} = \sqrt{900+1600} = \sqrt{2500}\\[5pt]   | ||
| + | &= \sqrt{25\cdot 100} = \sqrt{5^{2}\cdot 10^{2}} = 5\cdot 10 = 50\,\textrm{.}   | ||
| + | \end{align}</math>}}  | ||
Current revision
A right-angled triangle is a triangle in which one of the angles is 90°. The side which is opposite the 90°-angle is called the hypotenuse (marked x in the triangle) and the others are called opposite and the adjacent.
With the help of the Pythagorean theorem, we can write a relation between the sides of a right-angled triangle
| \displaystyle x^2 = 30^2 + 40^2\,\textrm{.} | 
This equation gives us that
| \displaystyle \begin{align}
 x &= \sqrt{30^{2}+40^{2}} = \sqrt{900+1600} = \sqrt{2500}\\[5pt] &= \sqrt{25\cdot 100} = \sqrt{5^{2}\cdot 10^{2}} = 5\cdot 10 = 50\,\textrm{.} \end{align}  | 
