From Förberedande kurs i matematik 1

Revision as of 09:53, 2 April 2008 (edit) Oskar (Talk | contribs) (Ny sida: {{NAVCONTENT_START}} <center> Bild:3_3_5d.gif </center> {{NAVCONTENT_STOP}}) ← Previous diff		Current revision (07:31, 2 October 2008) (edit) (undo) Tek (Talk | contribs) m
(3 intermediate revisions not shown.)
Line 1:		Line 1:
-	{{NAVCONTENT_START}}	+	Since <math>e^1 = e</math>, <math>\ln e = 1</math> and we have that <math>\ln e-1 = 1-1 = 0\,</math>.
-	<center> [[Bild:3_3_5d.gif]] </center>	+
-	{{NAVCONTENT_STOP}}	+

---

Current revision

Since \displaystyle e^1 = e, \displaystyle \ln e = 1 and we have that \displaystyle \ln e-1 = 1-1 = 0\,.