Solution 4.4:1b
From Förberedande kurs i matematik 1
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| - | {{  | + | The easiest angle to find is   | 
| - | <  | + | <math>v={\pi }/{3}\;</math>  | 
| - | {{  | + | in the first quadrant. When we draw the unit circle, we see that the angle which makes the same angle with the positive   | 
| + | <math>x</math>  | ||
| + | -axis as  | ||
| + | <math>v={\pi }/{3}\;</math>, but is under the   | ||
| + | <math>x</math>  | ||
| + | -axis, also has a cosine value of    | ||
| + | <math>{1}/{2}\;</math>  | ||
| + | (same   | ||
| + | <math>x</math>  | ||
| + | -coordinate).  | ||
| + | |||
[[Image:4_4_1_b.gif|center]]  | [[Image:4_4_1_b.gif|center]]  | ||
| + | |||
| + | There are thus two angles,   | ||
| + | <math>v={\pi }/{3}\;</math>  | ||
| + | and   | ||
| + | <math>v=2\pi -{\pi }/{3}\;={5\pi }/{3}\;</math>  | ||
| + | which have their cosine value equal to  | ||
| + | <math>\frac{1}{2}</math>.  | ||
Revision as of 12:31, 30 September 2008
The easiest angle to find is \displaystyle v={\pi }/{3}\; in the first quadrant. When we draw the unit circle, we see that the angle which makes the same angle with the positive \displaystyle x -axis as \displaystyle v={\pi }/{3}\;, but is under the \displaystyle x -axis, also has a cosine value of \displaystyle {1}/{2}\; (same \displaystyle x -coordinate).
There are thus two angles, \displaystyle v={\pi }/{3}\; and \displaystyle v=2\pi -{\pi }/{3}\;={5\pi }/{3}\; which have their cosine value equal to \displaystyle \frac{1}{2}.

