Solution 3.1:2c

From Förberedande kurs i matematik 1

(Difference between revisions)
Jump to: navigation, search
Current revision (07:56, 30 September 2008) (edit) (undo)
m
 
Line 1: Line 1:
-
The expression
+
The expression <math>-3^2</math> means <math>-(3^2)= -9</math> (and not <math>(-3)^2</math>) and so we have that
-
<math>-\text{3}^{\text{2 }}</math>
+
-
means
+
-
<math>-\left( \text{3} \right)^{\text{2}}\text{ }=-\text{9 }</math>
+
-
(and not
+
-
<math>\left( -\text{3} \right)^{\text{2}}</math>
+
-
) and so we have
+
 +
{{Displayed math||<math>\sqrt{-3^2} = \sqrt{-9}\,\textrm{.}</math>}}
-
The root expression
+
The root expression <math>\sqrt{-9}</math> is not defined because there is no number which, when multiplied by itself, gives <math>-9</math>.
-
<math>\sqrt{-9}</math>
+
-
is not defined because there is no number which, when multiplied by itself, gives
+
-
<math>-\text{9}</math>.
+

Current revision

The expression \displaystyle -3^2 means \displaystyle -(3^2)= -9 (and not \displaystyle (-3)^2) and so we have that

\displaystyle \sqrt{-3^2} = \sqrt{-9}\,\textrm{.}

The root expression \displaystyle \sqrt{-9} is not defined because there is no number which, when multiplied by itself, gives \displaystyle -9.

Retrieved from "http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-ImperialCollege/index.php/Solution_3.1:2c"