Solution 2.2:8c
From Förberedande kurs i matematik 1
(Difference between revisions)
m |
|||
| Line 1: | Line 1: | ||
| - | By moving the term in | + | By moving the term in ''x'' over to the right-hand side and dividing by 3, the inequality can be rewritten as |
| - | + | ||
| - | over to the right-hand side and dividing by | + | |
| - | + | ||
| + | {{Displayed math||<math>y\le 2-\frac{2}{3}x\,\textrm{.}</math>}} | ||
| - | <math>y | + | Then, we see that the area that we should shade consists of all the points under the straight line <math>y=2-\tfrac{2}{3}x\,</math>. |
| - | Then, we see that the area that we should shade consists of all the points under the straight line | ||
| - | <math>y=2-\frac{2}{3}x</math>. | ||
| - | |||
| - | |||
| - | {{NAVCONTENT_START}} | ||
| - | |||
| - | {{NAVCONTENT_STOP}} | ||
[[Image:2_2_8_c.gif|center]] | [[Image:2_2_8_c.gif|center]] | ||
Current revision
By moving the term in x over to the right-hand side and dividing by 3, the inequality can be rewritten as
| \displaystyle y\le 2-\frac{2}{3}x\,\textrm{.} |
Then, we see that the area that we should shade consists of all the points under the straight line \displaystyle y=2-\tfrac{2}{3}x\,.

