From Förberedande kurs i matematik 1

Revision as of 15:59, 14 August 2008 (edit) Martin (Talk | contribs) ← Previous diff		Current revision (12:54, 24 September 2008) (edit) (undo) Tek (Talk | contribs) m
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-	{{NAVCONTENT_START}}	+	The line should go through the points (5,0) and (0,-8) which must therefore satisfy the equation of the line <math>y=kx+m</math>, i.e.
-	[[Bild:S1_2_2_5_e.jpg|400px]]	+
-	<!--<center> [[Bild:2_2_5e.gif]] </center>-->	+	{{Displayed math||<math>0=k\cdot 5+m\qquad\text{and}\qquad -8 = k\cdot 0+m\,\textrm{.}</math>}}
-	{{NAVCONTENT_STOP}}	+
		+	From the second equation, we get <math>m=-8</math> and substituting this into the first equation gives
		+
		+	{{Displayed math||<math>0=5k-8\quad\Leftrightarrow\quad k={8}/{5}\,\textrm{.}</math>}}
		+
		+	The slope of the line is 8/5.
		+
		+
		+	<center>[[Image:S1_2_2_5_e.jpg|400px]]</center>

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Current revision

The line should go through the points (5,0) and (0,-8) which must therefore satisfy the equation of the line \displaystyle y=kx+m, i.e.

\displaystyle 0=k\cdot 5+m\qquad\text{and}\qquad -8 = k\cdot 0+m\,\textrm{.}

From the second equation, we get \displaystyle m=-8 and substituting this into the first equation gives

\displaystyle 0=5k-8\quad\Leftrightarrow\quad k={8}/{5}\,\textrm{.}

The slope of the line is 8/5.