Solution 2.1:1b

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m (Lösning 2.1:1b moved to Solution 2.1:1b: Robot: moved page)
Current revision (07:41, 23 September 2008) (edit) (undo)
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When the factor <math>xy</math> is multiplied by the expression inside the brackets, <math> 1+x+x^2 </math>, the distributive rule gives that all three terms <math>1</math>, <math>x</math> and <math>-x^2</math> are multiplied by <math>xy</math>,
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When the factor <math>xy</math> is multiplied by the expression inside the brackets, <math> 1+x+x^2 </math>, the distributive rule gives that all three terms <math>1</math>, <math>x</math> and <math>-x^2</math> are multiplied by <math>xy</math>;
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<math>
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{{Displayed math||<math>\begin{align}
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\qquad
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(1+x-x^2) &= 1\cdot xy + x\cdot xy -x^2\cdot xy\\[3pt]
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\begin{align}
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&= xy+x^2y-x^3y\,\textrm{.}
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(1+x-x^2) &= 1\cdot xy + x\cdot xy -x^2\cdot xy \\
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&= xy+x^2y-x^3y
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\end{align}
\end{align}
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</math>
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</math>}}
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<!-- <center> [[Image:2_1_1b.gif]] </center> -->
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Current revision

When the factor \displaystyle xy is multiplied by the expression inside the brackets, \displaystyle 1+x+x^2 , the distributive rule gives that all three terms \displaystyle 1, \displaystyle x and \displaystyle -x^2 are multiplied by \displaystyle xy,

\displaystyle \begin{align}

(1+x-x^2) &= 1\cdot xy + x\cdot xy -x^2\cdot xy\\[3pt] &= xy+x^2y-x^3y\,\textrm{.} \end{align}

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