From Förberedande kurs i matematik 1

Revision as of 15:10, 26 March 2008 (edit) Lina (Talk | contribs) (Ny sida: {{NAVCONTENT_START}} <center> Bild:1_3_5e.gif </center> {{NAVCONTENT_STOP}}) ← Previous diff		Current revision (14:30, 22 September 2008) (edit) (undo) Tek (Talk | contribs)
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-	{{NAVCONTENT_START}}	+	Individually, <math>3^{1\textrm{.}4}</math> and <math>3^{0\textrm{.}6}</math> are difficult to calculate, but when multiplied together
-	<center> [[Bild:1_3_5e.gif]] </center>	+
-	{{NAVCONTENT_STOP}}	+	{{Displayed math||<math>3^{1\textrm{.}4}\cdot 3^{0\textrm{.}6} = 3^{1\textrm{.}4+0\textrm{.}6} = 3^{2} = 3\cdot 3 = 9</math>}}
		+
		+	on using the power rules.

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Current revision

Individually, \displaystyle 3^{1\textrm{.}4} and \displaystyle 3^{0\textrm{.}6} are difficult to calculate, but when multiplied together

\displaystyle 3^{1\textrm{.}4}\cdot 3^{0\textrm{.}6} = 3^{1\textrm{.}4+0\textrm{.}6} = 3^{2} = 3\cdot 3 = 9

on using the power rules.