Solution 1.3:3b

From Förberedande kurs i matematik 1

(Difference between revisions)
Jump to: navigation, search
Current revision (13:07, 22 September 2008) (edit) (undo)
m
 
Line 1: Line 1:
-
If we divide
+
If we divide 243 successively by 3, we see that
-
<math>243</math>
+
-
successively by
+
-
<math>3</math>, we see that
+
-
 
+
{{Displayed math||<math>\begin{align}
-
<math>\begin{align}
+
243 &= 3\cdot 81 = 3\cdot 3\cdot 27 = 3\cdot 3\cdot 3\cdot 9 \\[5pt]
-
& 243=3\centerdot 81=3\centerdot 3\centerdot 27=3\centerdot 3\centerdot 3\centerdot 9 \\
+
&= 3\cdot 3\cdot 3\cdot 3\cdot 3 = 3^{5}\,\textrm{.}
-
& \\
+
\end{align}</math>}}
-
& =3\centerdot 3\centerdot 3\centerdot 3\centerdot 3=3^{5} \\
+
-
\end{align}</math>
+

Current revision

If we divide 243 successively by 3, we see that

\displaystyle \begin{align}

243 &= 3\cdot 81 = 3\cdot 3\cdot 27 = 3\cdot 3\cdot 3\cdot 9 \\[5pt] &= 3\cdot 3\cdot 3\cdot 3\cdot 3 = 3^{5}\,\textrm{.} \end{align}

Retrieved from "http://wiki.sommarmatte.se/wikis/2009/bridgecourse1-ImperialCollege/index.php/Solution_1.3:3b"