Answer 2.1:1
From Förberedande kurs i matematik 1
(Difference between revisions)
			  			                                                      
		          
			 (Ny sida: ===Övning 2.1:1=== <div class="ovning"> Utveckla {| width="100%" cellspacing="10px" |a) |width="33%" | <math>3x(x-1)</math> |b) |width="33%"  | <math>(1+x-x^2)xy</math> |c) |width="33%" | ...)  | 
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| Line 1: | Line 1: | ||
| - | ===  | + | ===Facit 2.1:1===  | 
<div class="ovning">  | <div class="ovning">  | ||
Utveckla  | Utveckla  | ||
{| width="100%" cellspacing="10px"  | {| width="100%" cellspacing="10px"  | ||
|a)  | |a)  | ||
| - | |width="33%" | <math>3x  | + | |width="33%" | <math>3x^2-3x</math>  | 
|b)  | |b)  | ||
| - | |width="33%"  | <math>  | + | |width="33%"  | <math>xy+x^2y-x^3y</math>  | 
|c)  | |c)  | ||
| - | |width="33%" | <math>-  | + | |width="33%" | <math>-4x^2+x^2y^2</math>  | 
|-  | |-  | ||
|d)  | |d)  | ||
| - | || <math>x^3y  | + | || <math>x^3y-x^2y+x^3y^2</math>  | 
|e)  | |e)  | ||
| - | ||<math>   | + | ||<math> x^2-14x+49</math>  | 
|f)  | |f)  | ||
| - | ||<math>   | + | ||<math> 16y^2+40y+25</math>  | 
|-  | |-  | ||
|g)  | |g)  | ||
| - | ||<math>  | + | ||<math>9x^6-6x^3y^2+y^4</math>  | 
|h)  | |h)  | ||
| - | ||<math>   | + | ||<math> 9x^{10}+30x^8+25x^6</math>  | 
|}  | |}  | ||
Revision as of 09:36, 31 March 2008
Facit 2.1:1
Utveckla
| a) | \displaystyle 3x^2-3x | b) | \displaystyle xy+x^2y-x^3y | c) | \displaystyle -4x^2+x^2y^2 | 
| d) | \displaystyle x^3y-x^2y+x^3y^2 | e) | \displaystyle x^2-14x+49 | f) | \displaystyle 16y^2+40y+25 | 
| g) | \displaystyle 9x^6-6x^3y^2+y^4 | h) | \displaystyle 9x^{10}+30x^8+25x^6 | 
