Answer 5.1:6

From Förberedande kurs i matematik 1

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  • (cur) (last) 14:26, 28 January 2009 Tek (Talk | contribs) (228 bytes) (New page: {| width="100%" cellspacing="10px" |a) |width="100%" | \ln(4\times 3)=\ln 4+\ln 3 |- |b) |width="100%" | \ln(4-3)\ne \ln 4-\ln 3 |- |c) |width="100%" | \log_{2}4 = \dfrac{\ln 4}{\ln 2} |- ...)
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