Solution 4.3:4c - Revision history

Tek at 14:12, 9 October 2008

Tek — Thu, 09 Oct 2008 14:12:41 GMT

←Older revision		Revision as of 14:12, 9 October 2008
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	The formula for double angles gives		The formula for double angles gives

		+	{{Displayed math\|\|<math>\sin 2v=2\sin v\cos v</math>}}

-	<math>\sin 2v=2\~~sin v\cos v~~</math>	+	and from exercise b, we have <math>\sin v = \sqrt{1-b^2}\,</math>. Thus,

-		+	{{Displayed math\|\|<math>\sin 2v = 2b\sqrt{1-b^2}\,\textrm{.}</math>}}
-	~~and from exercise b, we have~~	+
-	~~<math>\sin v=\sqrt~~{~~1-b^~~{~~2}}</~~math>	+
-		+
-		+
-	~~Thus,~~	+
-		+
-		+
-	<math>\sin 2v=2b\sqrt{1-b^{2}}</math>	+

Ian — Mon, 29 Sep 2008 11:44:59 GMT

←Older revision		Revision as of 11:44, 29 September 2008
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-	{{~~NAVCONTENT_START~~}}	+	The formula for double angles gives
-	~~<center> [[Image:4_3_4c.gif]]~~ </~~center~~>	+
-	{{~~NAVCONTENT_STOP~~}}	+
		+	<math>\sin 2v=2\sin v\cos v</math>
		+
		+
		+	and from exercise b, we have
		+	<math>\sin v=\sqrt{1-b^{2}}</math>
		+
		+
		+	Thus,
		+
		+
		+	<math>\sin 2v=2b\sqrt{1-b^{2}}</math>

Tekbot — Tue, 09 Sep 2008 09:54:43 GMT

←Older revision

Revision as of 09:54, 9 September 2008

Tekbot — Thu, 21 Aug 2008 07:14:29 GMT

Robot: Automated text replacement (-[[Bild: +[[Image:)

Oskar — Thu, 03 Apr 2008 09:48:33 GMT

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