Solution 4.2:1d - Revision history

Tek at 14:10, 8 October 2008

Tek — Wed, 08 Oct 2008 14:10:18 GMT

←Older revision		Revision as of 14:10, 8 October 2008
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		+	The side marked ''x'' is the hypotenuse in the right-angled triangle and the side of length 16 is the adjacent to the angle of 20°.
		+
	[[Image:4_2_1_d.gif\|center]]		[[Image:4_2_1_d.gif\|center]]

-	~~The side marked~~	+	By writing the quotient for <math>\cos 20^{\circ}</math>, we obtain the relation
-	~~<math>x</math>~~	+
-	~~is the hypotenuse in the right-angled triangle and the side of length~~	+
-	~~<math>\text{16}</math>~~	+
-	~~is the adjacent to the angle of~~	+
-	~~<math>\text{2}0^{\circ }</math>.~~	+
-		+
-		+
-	By writing the quotient for	+
-	<math>\~~text{cos20}~~^{\circ }</math>, we obtain the relation	+
-		+
-		+
-	~~<math>\text{cos20}^{\circ }=\frac{16}{x}</math>~~	+

		+	{{Displayed math\|\|<math>\cos 20^{\circ} = \frac{16}{x}</math>}}

	and this gives		and this gives

-		+	{{Displayed math\|\|<math>x = \frac{16}{\cos20^{\circ}}\quad ({}\approx 17\textrm{.}0)\,\textrm{.}</math>}}
-	<math>x=\frac{16}{\~~text{~~cos20}^{\circ }}\quad ~~\left~~( \approx 17.0 ~~\right~~).</math>	+

Ian — Sun, 28 Sep 2008 11:08:32 GMT

←Older revision		Revision as of 11:08, 28 September 2008
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-	<center> [[Image:4_2_1d.gif]] </center>
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	[[Image:4_2_1_d.gif\|center]]		[[Image:4_2_1_d.gif\|center]]
		+
		+	The side marked
		+	<math>x</math>
		+	is the hypotenuse in the right-angled triangle and the side of length
		+	<math>\text{16}</math>
		+	is the adjacent to the angle of
		+	<math>\text{2}0^{\circ }</math>.
		+
		+
		+	By writing the quotient for
		+	<math>\text{cos20}^{\circ }</math>, we obtain the relation
		+
		+
		+	<math>\text{cos20}^{\circ }=\frac{16}{x}</math>
		+
		+
		+	and this gives
		+
		+
		+	<math>x=\frac{16}{\text{cos20}^{\circ }}\quad \left( \approx 17.0 \right).</math>

Tekbot — Tue, 09 Sep 2008 09:40:43 GMT

←Older revision

Revision as of 09:40, 9 September 2008

Tekbot — Thu, 21 Aug 2008 07:07:29 GMT

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Madde — Fri, 15 Aug 2008 12:50:25 GMT

Oskar — Wed, 02 Apr 2008 15:43:18 GMT

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