Solution 4.2:1c - Revision history

Tek at 14:05, 8 October 2008

Tek — Wed, 08 Oct 2008 14:05:30 GMT

←Older revision		Revision as of 14:05, 8 October 2008
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	The difficulty is to recognize the sides in the right-angled triangle. A simple rule of thumb is that the hypotenuse is the side which is opposite the right angle (it is also the longest side in the triangle). The adjacent is the side which lies near to the angle that we are considering and the opposite is the third side.		The difficulty is to recognize the sides in the right-angled triangle. A simple rule of thumb is that the hypotenuse is the side which is opposite the right angle (it is also the longest side in the triangle). The adjacent is the side which lies near to the angle that we are considering and the opposite is the third side.

-		+	[[Image:4_2_1_c.gif\|center]]

-	The opposite is given, whilst it is the adjacent that we are looking for. The ~~tan~~ of the angle is given by	+	The opposite is given, whilst it is the adjacent that we are looking for. The tangent of the angle is given by
-		+
-		+
-	~~<math>\tan 40^{\circ }=\frac{14}{x}</math>~~	+

		+	{{Displayed math\|\|<math>\tan 40^{\circ } = \frac{14}{x}</math>}}

	and thus		and thus

-		+	{{Displayed math\|\|<math>x = \frac{14}{\tan 40^{\circ }}\quad \left( \approx 16\textrm{.}7 \right)\,\textrm{.}</math>}}
-	<math>x=\frac{14}{\tan 40^{\circ }}\quad \left( \approx 16.7 \right)</math>	+

Ian at 11:03, 28 September 2008

Ian — Sun, 28 Sep 2008 11:03:33 GMT

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-	<center> [[Image:4_2_1c-1(2).gif]] </center>
-	{{NAVCONTENT_STOP}}
-	{{NAVCONTENT_START}}
-	<center> [[Image:4_2_1c-2(2).gif]] </center>
-	{{NAVCONTENT_STOP}}
	[[Image:4_2_1_c.gif\|center]]		[[Image:4_2_1_c.gif\|center]]
		+
		+	The difficulty is to recognize the sides in the right-angled triangle. A simple rule of thumb is that the hypotenuse is the side which is opposite the right angle (it is also the longest side in the triangle). The adjacent is the side which lies near to the angle that we are considering and the opposite is the third side.
		+
		+
		+
		+	The opposite is given, whilst it is the adjacent that we are looking for. The tan of the angle is given by
		+
		+
		+	<math>\tan 40^{\circ }=\frac{14}{x}</math>
		+
		+
		+	and thus
		+
		+
		+	<math>x=\frac{14}{\tan 40^{\circ }}\quad \left( \approx 16.7 \right)</math>

Tekbot: Lösning 4.2:1c moved to Solution 4.2:1c: Robot: moved page

Tekbot — Tue, 09 Sep 2008 09:40:23 GMT

Lösning 4.2:1c moved to Solution 4.2:1c: Robot: moved page

←Older revision

Revision as of 09:40, 9 September 2008

Tekbot: Robot: Automated text replacement (-[[Bild: +[[Image:)

Tekbot — Thu, 21 Aug 2008 07:07:19 GMT

Robot: Automated text replacement (-[[Bild: +[[Image:)

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-	[[~~Bild~~:4_2_1_c.gif\|center]]	+	[[Image:4_2_1_c.gif\|center]]

Madde at 12:49, 15 August 2008

Madde — Fri, 15 Aug 2008 12:49:42 GMT

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Oskar: Ny sida: {{NAVCONTENT_START}} Bild:4_2_1c-1(2).gif {{NAVCONTENT_STOP}} {{NAVCONTENT_START}} Bild:4_2_1c-2(2).gif {{NAVCONTENT_STOP}}

Oskar — Wed, 02 Apr 2008 15:42:23 GMT

Ny sida: {{NAVCONTENT_START}} <center> Bild:4_2_1c-1(2).gif </center> {{NAVCONTENT_STOP}} {{NAVCONTENT_START}} <center> Bild:4_2_1c-2(2).gif </center> {{NAVCONTENT_STOP}}

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