Solution 4.1:1 - Revision history

Tek at 07:10, 3 October 2008

Tek — Fri, 03 Oct 2008 07:10:18 GMT

←Older revision		Revision as of 07:10, 3 October 2008
Line 1:		Line 1:
-	The only thing we really need to remember is that one ~~turn~~ corresponds to	+	The only thing we really need to remember is that one revolution corresponds to
-	~~<math>\text{36}0^{\text{o}}</math>~~	+	360° or <math>2\pi</math> radians. Then we get:
-	or	+
-	<math>~~\text{~~2}\pi </math>	+
-	radians. Then we get:	+

-	a)	+	{\|
-	<math>\frac{1}{4}~~</math>~~	+	\|\|a)
-	~~turn~~	+	\|width="100%"\|<math>\frac{1}{4}\ \text{revolution} = \frac{1}{4}\cdot 360^{\circ} = 90^{\circ}</math> and
-	~~<math>~~=\frac{1}{4}\~~centerdot~~ 360^{\circ }=90^{\circ }</math>	+	\|-
-	and	+	\|\|
-		+	\|width="100%"\|<math>\frac{1}{4}\ \text{revolution} = \frac{1}{4}\cdot 2\pi\ \text{radians} = \frac{\pi}{2}\ \text{radians,}</math>
-	<math>\frac{1}{4}~~</math>~~	+	\|-
-	~~turn~~	+	\|height="10px"\|
-	~~<math>~~=\frac{1}{4}\~~centerdot~~ 2\pi ~~</math>~~	+	\|-
-	radians	+	\|\|b)
-	~~<math>~~=\frac{\pi }{2}</math>	+	\|width="100%"\|<math>\frac{3}{8}\ \text{revolution} = \frac{3}{8}\cdot 360^{\circ} = 135^{\circ}</math> and
-	~~radians,~~	+	\|-
-		+	\|\|
-		+	\|\|<math>\frac{3}{8}\ \text{revolution} = \frac{3}{8}\cdot 2\pi\ \text{radians} = \frac{3\pi}{4}\ \text{radians,}</math>
-	b)	+	\|-
-	<math>\frac{3}{8}~~</math>~~	+	\|height="10px"\|
-	~~turn~~	+	\|-
-	~~<math>~~=\frac{3}{8}\~~centerdot~~ 360^{\circ }=135^{\circ }</math>	+	\|\|c)
-	and	+	\|width="100%"\|<math>-\frac{2}{3}\ \text{revolution} = -\frac{2}{3}\cdot 360^{\circ} = -240^{\circ}</math> and
-		+	\|-
-	<math>\frac{3}{8}~~</math>~~	+	\|\|
-	~~turn~~	+	\|width="100%"\|<math>-\frac{2}{3}\ \text{revolution} = -\frac{2}{3}\cdot 2\pi\ \text{radians} = -\frac{4\pi}{3}\ \text{radians,}</math>
-	~~<math>~~=\frac{3}{8}\~~centerdot~~ 2\pi ~~</math>~~	+	\|-
-	radians	+	\|height="10px"\|
-	~~<math>~~=\frac{3\pi }{4}</math>	+	\|-
-	~~radians,~~	+	\|\|d)
-		+	\|width="100%"\|<math>\frac{97}{12}\ \text{revolution} = \frac{97}{12}\cdot 360^{\circ} = 2910^{\circ}</math> and
-		+	\|-
-		+	\|\|
-	c)	+	\|width="100%"\|<math>\frac{97}{12}\ \text{revolution} = \frac{97}{12}\cdot 2\pi\ \text{radians} = \frac{97\pi}{6}\ \text{radians.}</math>
-	<math>-\frac{2}{3}~~</math>~~	+	\|}
-	~~turn~~	+
-	~~<math>~~=-\frac{2}{3}\~~centerdot~~ 360^{\circ }=-240^{\circ }</math>	+
-	and	+
-		+
-	<math>-\frac{2}{3}~~</math>~~	+
-	~~turn~~	+
-	~~<math>~~=-\frac{2}{3}\~~centerdot~~ 2\pi ~~</math>~~	+
-	radians	+
-	~~<math>~~=-\frac{4\pi }{3}</math>	+
-	~~radians,~~	+
-		+
-		+
-	d)	+
-	<math>\frac{97}{12}~~</math>~~	+
-	~~turn~~	+
-	~~<math>~~=\frac{97}{12}\~~centerdot~~ 360^{\circ }=2910^{\circ }</math>	+
-	and	+
-		+
-	<math>\frac{97}{12}~~</math>~~	+
-	~~turn~~	+
-	~~<math>~~=\frac{97}{12}\~~centerdot~~ 2\pi ~~</math>~~	+
-	radians	+
-	~~<math>~~=\frac{97\pi }{6}</math>	+
-	~~radians,~~	+

Ian at 12:31, 26 September 2008

Ian — Fri, 26 Sep 2008 12:31:04 GMT

←Older revision		Revision as of 12:31, 26 September 2008
Line 1:		Line 1:
-	{{~~NAVCONTENT_START~~}}	+	The only thing we really need to remember is that one turn corresponds to
-	<~~center~~> ~~[[Image:4_1_1~~.~~gif]]~~ </~~center~~>	+	<math>\text{36}0^{\text{o}}</math>
-	{{~~NAVCONTENT_STOP~~}}	+	or
		+	<math>\text{2}\pi </math>
		+	radians. Then we get:
		+
		+	a)
		+	<math>\frac{1}{4}</math>
		+	turn
		+	<math>=\frac{1}{4}\centerdot 360^{\circ }=90^{\circ }</math>
		+	and
		+
		+	<math>\frac{1}{4}</math>
		+	turn
		+	<math>=\frac{1}{4}\centerdot 2\pi </math>
		+	radians
		+	<math>=\frac{\pi }{2}</math>
		+	radians,
		+
		+
		+	b)
		+	<math>\frac{3}{8}</math>
		+	turn
		+	<math>=\frac{3}{8}\centerdot 360^{\circ }=135^{\circ }</math>
		+	and
		+
		+	<math>\frac{3}{8}</math>
		+	turn
		+	<math>=\frac{3}{8}\centerdot 2\pi </math>
		+	radians
		+	<math>=\frac{3\pi }{4}</math>
		+	radians,
		+
		+
		+
		+	c)
		+	<math>-\frac{2}{3}</math>
		+	turn
		+	<math>=-\frac{2}{3}\centerdot 360^{\circ }=-240^{\circ }</math>
		+	and
		+
		+	<math>-\frac{2}{3}</math>
		+	turn
		+	<math>=-\frac{2}{3}\centerdot 2\pi </math>
		+	radians
		+	<math>=-\frac{4\pi }{3}</math>
		+	radians,
		+
		+
		+	d)
		+	<math>\frac{97}{12}</math>
		+	turn
		+	<math>=\frac{97}{12}\centerdot 360^{\circ }=2910^{\circ }</math>
		+	and
		+
		+	<math>\frac{97}{12}</math>
		+	turn
		+	<math>=\frac{97}{12}\centerdot 2\pi </math>
		+	radians
		+	<math>=\frac{97\pi }{6}</math>
		+	radians,

Tekbot: Lösning 4.1:1 moved to Solution 4.1:1: Robot: moved page

Tekbot — Tue, 09 Sep 2008 09:33:03 GMT

Lösning 4.1:1 moved to Solution 4.1:1: Robot: moved page

←Older revision

Revision as of 09:33, 9 September 2008

Tekbot: Robot: Automated text replacement (-[[Bild: +[[Image:)

Tekbot — Thu, 21 Aug 2008 07:03:39 GMT

Robot: Automated text replacement (-[[Bild: +[[Image:)

←Older revision		Revision as of 07:03, 21 August 2008
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	{{NAVCONTENT_START}}		{{NAVCONTENT_START}}
-	<center> [[~~Bild~~:4_1_1.gif]] </center>	+	<center> [[Image:4_1_1.gif]] </center>
	{{NAVCONTENT_STOP}}		{{NAVCONTENT_STOP}}

Oskar at 12:53, 2 April 2008

Oskar — Wed, 02 Apr 2008 12:53:29 GMT

←Older revision		Revision as of 12:53, 2 April 2008
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	{{NAVCONTENT_START}}		{{NAVCONTENT_START}}
-	<center> [[Bild:~~4_1_1a~~.gif]] </center>	+	<center> [[Bild:4_1_1.gif]] </center>
	{{NAVCONTENT_STOP}}		{{NAVCONTENT_STOP}}

Oskar: Ny sida: {{NAVCONTENT_START}} Bild:4_1_1a.gif {{NAVCONTENT_STOP}}

Oskar — Wed, 02 Apr 2008 12:51:54 GMT

Ny sida: {{NAVCONTENT_START}} <center> Bild:4_1_1a.gif </center> {{NAVCONTENT_STOP}}

New page

{{NAVCONTENT_START}}
<center> [[Bild:4_1_1a.gif]] </center>
{{NAVCONTENT_STOP}}