Solution 3.1:2b - Revision history

Tek at 07:52, 30 September 2008

Tek — Tue, 30 Sep 2008 07:52:47 GMT

←Older revision		Revision as of 07:52, 30 September 2008
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-	That which is under the root sign is the same as	+	That which is under the root sign is the same as <math>(-3)^{2} = 9</math> and because
-	<math>~~\left~~( -~~\text{~~3~~} \right~~)^~~{\text~~{2}}=~~\text{~~9 }</math>	+	<math>9 = 3\cdot 3 = 3^{2}</math>, hence
-	and because	+
-	<math>~~\text{~~9}=~~\text{~~3}\~~centerdot \text{~~3}=~~\text{~~3}^~~{\text~~{2}}</math>, hence	+

		+	{{Displayed math\|\|<math>\sqrt{(-3)^{2}} = \sqrt{9} = 9^{1/2} = \bigl(3^{2}\bigr)^{1/2} = 3^{2\cdot\frac{1}{2}} = 3^{1} = 3</math>.}}

-	<math>\sqrt{\left( -3 \right)^{2}}=\sqrt{9}=9^{{1}/{2}\;}=\left( 3^{2} \right)^{{1}/{2}\;}=3^{2\centerdot \frac{1}{2}}=3^{1}=3</math>

-		+	Note:
-	~~NOTE~~:	+	The calculation <math>\sqrt{(-3)^{2}} = \bigl((-3)^{2}\bigr)^{1/2} = (-3)^{2\cdot \frac{1}{2}} = (-3)^1 = -3</math> is wrong at the second equals sign. Remember that the power rules apply when the base is positive.
-	The calculation	+
-	<math>\sqrt{~~\left~~( -3 ~~\right~~)^{2}}=\~~left~~( ~~\left~~( -3 ~~\right~~)^{2} \~~right~~)^{{1}/{2~~}\;~~}=~~\left~~( -3 ~~\right~~)^{2\~~centerdot~~ \frac{1}{2}}=~~\left~~( -3 ~~\right~~)^{1}=-3</math>	+
-		+
-	is wrong at the second equals sign. Remember that the power rules apply when the base is positive.	+

Ian — Mon, 22 Sep 2008 10:44:12 GMT

←Older revision		Revision as of 10:44, 22 September 2008
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-	{{~~NAVCONTENT_START~~}}	+	That which is under the root sign is the same as
-	<~~center~~> ~~[[Image:3_1_2b.gif]]~~ </~~center~~>	+	<math>\left( -\text{3} \right)^{\text{2}}=\text{9 }</math>
-	{{~~NAVCONTENT_STOP~~}}	+	and because
		+	<math>\text{9}=\text{3}\centerdot \text{3}=\text{3}^{\text{2}}</math>, hence
		+
		+
		+	<math>\sqrt{\left( -3 \right)^{2}}=\sqrt{9}=9^{{1}/{2}\;}=\left( 3^{2} \right)^{{1}/{2}\;}=3^{2\centerdot \frac{1}{2}}=3^{1}=3</math>
		+
		+
		+	NOTE:
		+	The calculation
		+	<math>\sqrt{\left( -3 \right)^{2}}=\left( \left( -3 \right)^{2} \right)^{{1}/{2}\;}=\left( -3 \right)^{2\centerdot \frac{1}{2}}=\left( -3 \right)^{1}=-3</math>
		+
		+	is wrong at the second equals sign. Remember that the power rules apply when the base is positive.

Tekbot — Tue, 09 Sep 2008 09:07:43 GMT

←Older revision

Revision as of 09:07, 9 September 2008

Tekbot — Thu, 21 Aug 2008 06:50:59 GMT

Robot: Automated text replacement (-[[Bild: +[[Image:)

Oskar — Tue, 01 Apr 2008 13:46:11 GMT

Ny sida: {{NAVCONTENT_START}} <center> Bild:3_1_2b.gif </center> {{NAVCONTENT_STOP}}

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