Solution 2.2:6a - Revision history

Tek at 13:00, 24 September 2008

Tek — Wed, 24 Sep 2008 13:00:07 GMT

←Older revision		Revision as of 13:00, 24 September 2008
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	According to the definition, the point of intersection between two lines is that point which lies on both lines; it must therefore satisfy the equations of both lines.		According to the definition, the point of intersection between two lines is that point which lies on both lines; it must therefore satisfy the equations of both lines.

-	If the point of intersection has coordinates	+	If the point of intersection has coordinates (''x'',''y''), then
-	~~<math>\left~~( x ~~\right.~~,~~\left.~~ y ~~\right~~)~~</math>~~, then	+

-	<math>y=3x+5</math>	+	{{Displayed math\|\|
		+	<math>\left\{\begin{align} y&=3x+5\,,\\ y&=0\,\textrm{.}\qquad\quad\text{(x-axis)}\end{align}\right.</math>}}

-	~~and~~	+	If we substitute <math>y=0</math> into the first equation, we obtain

-	<math>y=~~0</math>~~	+	{{Displayed math\|\|<math>0=3x+5,\qquad\text{i.e.}\quad x=-\frac{5}{3}\,\textrm{.}</math>}}
-	(	+
-	~~<math>~~x</math>	+
-	~~-axis)~~	+

-	~~If we substitute~~	+	The point of intersection is (-5/3,0).
-	~~<math>y=0<~~/~~math>~~	+
-	~~into the first equation~~, ~~we obtain~~	+


-	<~~math~~>~~0=3x+5</math>~~	+	<center>[[Image:2_2_6_a.gif\|center]]</center>
-	~~i.e.~~	+
-	~~<math>x=-\frac{5}{3}</math>~~	+
-		+
-		+
-	~~The point of intersection is~~	+
-	~~<math>\left( -\frac{5}{3} \right.,\left. 0 \right)</math>.~~	+
-		+
-		+
-	~~{{NAVCONTENT_START}}~~	+
-		+
-	[[Image:2_2_6_a.gif\|center]]	+
-	~~{{NAVCONTENT_STOP}}~~	+

Ian — Thu, 18 Sep 2008 10:16:05 GMT

←Older revision		Revision as of 10:16, 18 September 2008
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		+	According to the definition, the point of intersection between two lines is that point which lies on both lines; it must therefore satisfy the equations of both lines.
		+
		+	If the point of intersection has coordinates
		+	<math>\left( x \right.,\left. y \right)</math>, then
		+
		+	<math>y=3x+5</math>
		+
		+	and
		+
		+	<math>y=0</math>
		+	(
		+	<math>x</math>
		+	-axis)
		+
		+	If we substitute
		+	<math>y=0</math>
		+	into the first equation, we obtain
		+
		+
		+	<math>0=3x+5</math>
		+	i.e.
		+	<math>x=-\frac{5}{3}</math>
		+
		+
		+	The point of intersection is
		+	<math>\left( -\frac{5}{3} \right.,\left. 0 \right)</math>.
		+
		+
	{{NAVCONTENT_START}}		{{NAVCONTENT_START}}
-	~~<center> [[Image:2_2_6a.gif]] </center>~~	+
	[[Image:2_2_6_a.gif\|center]]		[[Image:2_2_6_a.gif\|center]]
	{{NAVCONTENT_STOP}}		{{NAVCONTENT_STOP}}

Tekbot — Tue, 09 Sep 2008 08:48:43 GMT

←Older revision

Revision as of 08:48, 9 September 2008

Tekbot — Thu, 21 Aug 2008 06:41:29 GMT

Robot: Automated text replacement (-[[Bild: +[[Image:)

Madde — Fri, 15 Aug 2008 11:16:41 GMT

Lina — Mon, 31 Mar 2008 14:52:52 GMT

Ny sida: {{NAVCONTENT_START}} <center> Bild:2_2_6a.gif </center> {{NAVCONTENT_STOP}}

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<center> [[Bild:2_2_6a.gif]] </center>
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