Solution 2.2:5e - Revision history

Tek at 12:54, 24 September 2008

Tek — Wed, 24 Sep 2008 12:54:31 GMT

←Older revision		Revision as of 12:54, 24 September 2008
Line 1:		Line 1:
-	The line should go through the points	+	The line should go through the points (5,0) and (0,-8) which must therefore satisfy the equation of the line <math>y=kx+m</math>, i.e.
-	~~<math>\left~~( 5 ~~\right.~~,~~\left.~~ 0 ~~\right~~)~~</math>~~	+
-	and	+
-	~~<math>\left~~( 0 ~~\right.~~,~~\left.~~ -8 ~~\right~~)~~</math>~~	+
-	which must therefore satisfy the equation of the line	+
-	<math>y=kx+m</math>, i.e.	+

		+	{{Displayed math\|\|<math>0=k\cdot 5+m\qquad\text{and}\qquad -8 = k\cdot 0+m\,\textrm{.}</math>}}

-	<math>~~0=k\centerdot 5+~~m</math>	+	From the second equation, we get <math>m=-8</math> and substituting this into the first equation gives

		+	{{Displayed math\|\|<math>0=5k-8\quad\Leftrightarrow\quad k={8}/{5}\,\textrm{.}</math>}}

-	~~From~~ the ~~other equation, we get~~	+	The slope of the line is 8/5.
-	~~<math>m=-~~8</~~math>~~	+
-	~~and substituting this into the first equation gives~~	+


-	<~~math~~>~~0=5k-8\ \Leftrightarrow \ k={8}/{5}\;</math>~~	+	<center>[[Image:S1_2_2_5_e.jpg\|400px]]</center>
-		+
-		+
-	~~The gradient of the line is~~	+
-	~~<math>{8}/{5}\;</math>.~~	+
-		+
-		+
-	~~{{NAVCONTENT_START}}~~	+
-	[[Image:S1_2_2_5_e.jpg\|400px]]	+
-	~~<!--<center> [[Image:2_2_5e.gif~~]] </center>~~-->~~	+
-	~~{{NAVCONTENT_STOP}}~~	+

Ian — Thu, 18 Sep 2008 10:05:46 GMT

←Older revision		Revision as of 10:05, 18 September 2008
Line 1:		Line 1:
		+	The line should go through the points
		+	<math>\left( 5 \right.,\left. 0 \right)</math>
		+	and
		+	<math>\left( 0 \right.,\left. -8 \right)</math>
		+	which must therefore satisfy the equation of the line
		+	<math>y=kx+m</math>, i.e.
		+
		+
		+	<math>0=k\centerdot 5+m</math>
		+
		+
		+	From the other equation, we get
		+	<math>m=-8</math>
		+	and substituting this into the first equation gives
		+
		+
		+	<math>0=5k-8\ \Leftrightarrow \ k={8}/{5}\;</math>
		+
		+
		+	The gradient of the line is
		+	<math>{8}/{5}\;</math>.
		+
		+
	{{NAVCONTENT_START}}		{{NAVCONTENT_START}}
	[[Image:S1_2_2_5_e.jpg\|400px]]		[[Image:S1_2_2_5_e.jpg\|400px]]
	<!--<center> [[Image:2_2_5e.gif]] </center>-->		<!--<center> [[Image:2_2_5e.gif]] </center>-->
	{{NAVCONTENT_STOP}}		{{NAVCONTENT_STOP}}

Tekbot — Tue, 09 Sep 2008 08:48:23 GMT

←Older revision

Revision as of 08:48, 9 September 2008

Tekbot — Thu, 21 Aug 2008 06:41:19 GMT

Robot: Automated text replacement (-[[Bild: +[[Image:)

Martin — Thu, 14 Aug 2008 15:59:24 GMT

Martin — Thu, 14 Aug 2008 15:58:05 GMT

Lina — Mon, 31 Mar 2008 14:51:01 GMT

Ny sida: {{NAVCONTENT_START}} <center> Bild:2_2_5e.gif </center> {{NAVCONTENT_STOP}}

New page

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<center> [[Bild:2_2_5e.gif]] </center>
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