Solution 2.1:8a - Revision history

Tek at 12:29, 23 September 2008

Tek — Tue, 23 Sep 2008 12:29:56 GMT

←Older revision		Revision as of 12:29, 23 September 2008
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-	An expression which consists of several fraction signs can be rewritten in terms of one fraction sign	+	An expression which consists of several fraction signs can be rewritten in terms of one fraction sign by systematically eliminating all partial fractions.
-	by systematically eliminating all partial fractions.	+

-	In our expression, we multiply the top and bottom of the main fraction by	+	In our expression, we multiply the top and bottom of the main fraction by <math>x+1</math> (so as to get rid of <math>x+1</math> from the numerator),
-	<math>x+1</math>	+
-	(so as to get rid of	+
-	<math>x+1</math>	+
-	from the numerator),	+

-		+	{{Displayed math\|\|<math>\frac{\,\dfrac{x}{x+1}\,}{3+x} = \frac{\,\dfrac{x}{x+1}\,}{3+x}\cdot\frac{x+1}{x+1} = \frac{\,\dfrac{x}{x+1}\cdot (x+1)\,}{\,(3+x)(x+1)\,} = \frac{x}{(3+x)(x+1)}\,\textrm{.}</math>}}
-	<math>\frac{\~~frac~~{x}{x+1}}{3+x}=\frac{\~~frac~~{x}{x+1}}{3+x}\~~centerdot~~ \frac{x+1}{x+1}=\frac{\~~frac~~{x}{x+1}\~~centerdot \left~~( x+1 ~~\right~~)}{\~~left~~( 3+x ~~\right~~)~~\left~~( x+1 \~~right)~~}=\frac{x}{~~\left~~( 3+x ~~\right~~)~~\left~~( x+1 ~~\right~~)}.</math>	+

Ian — Tue, 16 Sep 2008 13:08:07 GMT

←Older revision		Revision as of 13:08, 16 September 2008
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-	~~{{NAVCONTENT_START}}~~	+	An expression which consists of several fraction signs can be rewritten in terms of one fraction sign
-	<~~center~~> ~~[[Image:2_1_8a.gif]]~~ </~~center~~>	+	by systematically eliminating all partial fractions.
-	{{~~NAVCONTENT_STOP~~}}	+
		+	In our expression, we multiply the top and bottom of the main fraction by
		+	<math>x+1</math>
		+	(so as to get rid of
		+	<math>x+1</math>
		+	from the numerator),
		+
		+
		+	<math>\frac{\frac{x}{x+1}}{3+x}=\frac{\frac{x}{x+1}}{3+x}\centerdot \frac{x+1}{x+1}=\frac{\frac{x}{x+1}\centerdot \left( x+1 \right)}{\left( 3+x \right)\left( x+1 \right)}=\frac{x}{\left( 3+x \right)\left( x+1 \right)}.</math>

Tekbot — Tue, 09 Sep 2008 08:41:23 GMT

←Older revision

Revision as of 08:41, 9 September 2008

Tekbot — Thu, 21 Aug 2008 06:37:49 GMT

Robot: Automated text replacement (-[[Bild: +[[Image:)

Lina — Mon, 31 Mar 2008 11:22:33 GMT

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