Solution 2.1:1a - Revision history

Tek at 07:38, 23 September 2008

Tek — Tue, 23 Sep 2008 07:38:33 GMT

←Older revision		Revision as of 07:38, 23 September 2008
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	Using the distributivity rule, we can multiply the factor <math> 3x </math> into the bracket <math> (x-1) </math>. Each term in <math> (x-1)</math> is then to be multiplied by <math> 3x, </math>		Using the distributivity rule, we can multiply the factor <math> 3x </math> into the bracket <math> (x-1) </math>. Each term in <math> (x-1)</math> is then to be multiplied by <math> 3x, </math>

-	:<math> 3x(x-1)=3x\cdot x - 3x \cdot 1 = 3x^2-3x. </math>	+	{{Displayed math\|\|<math> 3x(x-1)=3x\cdot x - 3x \cdot 1 = 3x^2-3x\,\textrm{.}</math>}}

Tekbot — Tue, 09 Sep 2008 08:30:23 GMT

←Older revision

Revision as of 08:30, 9 September 2008

Tekbot — Thu, 21 Aug 2008 06:32:19 GMT

Robot: Automated text replacement (-[[Bild: +[[Image:)

←Older revision		Revision as of 06:32, 21 August 2008
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-	<!--center> [[~~Bild~~:2_1_1a.gif]] </center-->	+	<!--center> [[Image:2_1_1a.gif]] </center-->

	Using the distributivity rule, we can multiply the factor <math> 3x </math> into the bracket <math> (x-1) </math>. Each term in <math> (x-1)</math> is then to be multiplied by <math> 3x, </math>		Using the distributivity rule, we can multiply the factor <math> 3x </math> into the bracket <math> (x-1) </math>. Each term in <math> (x-1)</math> is then to be multiplied by <math> 3x, </math>

	:<math> 3x(x-1)=3x\cdot x - 3x \cdot 1 = 3x^2-3x. </math>		:<math> 3x(x-1)=3x\cdot x - 3x \cdot 1 = 3x^2-3x. </math>

Madde — Wed, 13 Aug 2008 08:15:52 GMT

←Older revision		Revision as of 08:15, 13 August 2008
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	<!--center> [[Bild:2_1_1a.gif]] </center-->		<!--center> [[Bild:2_1_1a.gif]] </center-->

-	Using the distributivity rule, we can multiply the factor <math> 3x </math> into the bracket <math> (x-1) </math>. Each term in <math> (x-1)</math> is then to be multiplied by <math> 3x. </math>	+	Using the distributivity rule, we can multiply the factor <math> 3x </math> into the bracket <math> (x-1) </math>. Each term in <math> (x-1)</math> is then to be multiplied by <math> 3x, </math>

-	:<math> 3x(x-1)=3x\cdot x - 3x \cdot 1 = 3x^2-3x </math>	+	:<math> 3x(x-1)=3x\cdot x - 3x \cdot 1 = 3x^2-3x. </math>

Madde — Wed, 13 Aug 2008 08:14:59 GMT

←Older revision		Revision as of 08:14, 13 August 2008
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-	~~{{NAVCONTENT_START}}~~	+	<!--center> [[Bild:2_1_1a.gif]] </center-->
-	<center> [[Bild:2_1_1a.gif]] </center>	+
-	~~{{NAVCONTENT_STOP}}~~	+	Using the distributivity rule, we can multiply the factor <math> 3x </math> into the bracket <math> (x-1) </math>. Each term in <math> (x-1)</math> is then to be multiplied by <math> 3x. </math>
		+
		+	:<math> 3x(x-1)=3x\cdot x - 3x \cdot 1 = 3x^2-3x </math>

Lina — Mon, 31 Mar 2008 07:33:16 GMT

Ny sida: {{NAVCONTENT_START}} <center> Bild:2_1_1a.gif </center> {{NAVCONTENT_STOP}}

New page

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<center> [[Bild:2_1_1a.gif]] </center>
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