Solution 1.3:5b - Revision history

Tek at 14:24, 22 September 2008

Tek — Mon, 22 Sep 2008 14:24:24 GMT

←Older revision		Revision as of 14:24, 22 September 2008
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-	If we use	+	If we use <math>4 = 2\cdot 2 = 2^{2}</math>, the power rules give
-	<math>4=2\~~centerdot~~ 2=2^{2}</math>, the power rules give	+

-		+	{{Displayed math\|\|<math>4^{-\frac{1}{2}} = \bigl( 2^{2}\bigr)^{-\frac{1}{2}} = 2^{2\cdot (-\frac{1}{2})} = 2^{-1} = \frac{1}{2}\,</math>.}}
-	<math>4^{-\frac{1}{2}}=\~~left~~( 2^{2} \~~right~~)^{-\frac{1}{2}}=2^{2\~~centerdot \left~~( -\frac{1}{2} ~~\right~~)}=2^{-1}=\frac{1}{2}</math>	+

Ian — Mon, 15 Sep 2008 12:01:54 GMT

←Older revision		Revision as of 12:01, 15 September 2008
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-	~~{{NAVCONTENT_START}}~~	+	If we use
-	<~~center~~> ~~[[Image:1_3_5b.gif]]~~ </~~center~~>	+	<math>4=2\centerdot 2=2^{2}</math>, the power rules give
-	{{~~NAVCONTENT_STOP~~}}	+
		+
		+	<math>4^{-\frac{1}{2}}=\left( 2^{2} \right)^{-\frac{1}{2}}=2^{2\centerdot \left( -\frac{1}{2} \right)}=2^{-1}=\frac{1}{2}</math>

Tekbot — Tue, 09 Sep 2008 08:26:43 GMT

←Older revision

Revision as of 08:26, 9 September 2008

Tekbot — Thu, 21 Aug 2008 06:30:29 GMT

Robot: Automated text replacement (-[[Bild: +[[Image:)

Lina — Wed, 26 Mar 2008 15:08:05 GMT

Ny sida: {{NAVCONTENT_START}} <center> Bild:1_3_5b.gif </center> {{NAVCONTENT_STOP}}

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