Solution 1.3:2a - Revision history

Tek at 12:53, 22 September 2008

Tek — Mon, 22 Sep 2008 12:53:25 GMT

←Older revision		Revision as of 12:53, 22 September 2008
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-	We can write every factor in the expression as a power of	+	We can write every factor in the expression as a power of 2,
-	~~<math>~~2~~</math>~~,	+
-		+
-		+
-	~~<math>\begin{align}~~	+
-	~~& 2=2^{1} \\~~	+
-	~~& \\~~	+
-	~~& 4=2\centerdot 2=2^{2} \\~~	+
-	~~& \\~~	+
-	~~& 8=2\centerdot 4=2\centerdot 2\centerdot 2=2^{3} \\~~	+
-	~~\end{align}</math>~~	+

		+	{{Displayed math\|\|<math>\begin{align}
		+	2 &= 2^{1}\,, \\
		+	4 &= 2\cdot 2 = 2^{2}\,,\\
		+	8 &= 2\cdot 4 = 2\cdot 2\cdot 2 = 2^{3}\,,
		+	\end{align}</math>}}

	which gives		which gives

-		+	{{Displayed math\|\|<math>2\cdot 4\cdot 8 = 2^{1}\cdot 2^{2}\cdot 2^{3} = 2^{1+2+3} = 2^{6}\,</math>.}}
-	<math>2\~~centerdot~~ 4\~~centerdot~~ 8=2^{1}\~~centerdot~~ 2^{2}\~~centerdot~~ 2^{3}=2^{1+2+3}=2^{6}</math>	+

Ian — Mon, 15 Sep 2008 11:12:49 GMT

←Older revision		Revision as of 11:12, 15 September 2008
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-	{{~~NAVCONTENT_START~~}}	+	We can write every factor in the expression as a power of
-	~~<center> [[Image:1_3_2a.gif]]~~ </~~center~~>	+	<math>2</math>,
-	{{~~NAVCONTENT_STOP~~}}	+
		+
		+	<math>\begin{align}
		+	& 2=2^{1} \\
		+	& \\
		+	& 4=2\centerdot 2=2^{2} \\
		+	& \\
		+	& 8=2\centerdot 4=2\centerdot 2\centerdot 2=2^{3} \\
		+	\end{align}</math>
		+
		+
		+	which gives
		+
		+
		+	<math>2\centerdot 4\centerdot 8=2^{1}\centerdot 2^{2}\centerdot 2^{3}=2^{1+2+3}=2^{6}</math>

Tekbot — Tue, 09 Sep 2008 08:22:03 GMT

←Older revision

Revision as of 08:22, 9 September 2008

Tekbot — Thu, 21 Aug 2008 06:28:09 GMT

Robot: Automated text replacement (-[[Bild: +[[Image:)

Lina — Wed, 26 Mar 2008 14:56:41 GMT

Ny sida: {{NAVCONTENT_START}} <center> Bild:1_3_2a.gif </center> {{NAVCONTENT_STOP}}

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