Solution 1.2:2c - Revision history

Tek at 12:15, 22 September 2008

Tek — Mon, 22 Sep 2008 12:15:12 GMT

←Older revision		Revision as of 12:15, 22 September 2008
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	We divide up the two numerators into the smallest possible integer factors,		We divide up the two numerators into the smallest possible integer factors,

-		+	{{Displayed math\|\|<math>\begin{align}
-	<math>\begin{align}	+	12 &= 2\cdot 6 = 2\cdot 2\cdot 3\,,\\
-	& 12=2\~~centerdot~~ 6=2\~~centerdot~~ 2\~~centerdot~~ 3 \\	+	14 &= 2\cdot 7\,\textrm{.} \\
-	& 14=2\~~centerdot~~ 7 \\	+	\end{align}</math>}}
-	\end{align}</math>	+

	The expression can thus be written as		The expression can thus be written as

		+	{{Displayed math\|\|
		+	<math>\frac{1}{2\cdot 2\cdot 3}-\frac{1}{2\cdot 7}\,</math>.}}

-	~~<math>\frac{1}{2\centerdot 2\centerdot 3}-\frac{1}{2\centerdot 7}</math>~~	+	Here, we see that the denominators have a factor 2 in common. We multiply the top and bottom of the first fraction by 7 and the second by <math>2\cdot 3</math>
-		+	i.e. we leave out the common factor 2, so that the fractions have the lowest common denominator <math>2\cdot 2\cdot 3\cdot 7</math>,
-	Here, we see that the denominators have a factor	+
-	~~<math>~~2~~</math>~~	+
-	in common. We multiply the top and bottom of the first fraction by	+
-	~~<math>~~7~~</math>~~	+
-	and the second by	+
-	<math>2\~~centerdot~~ 3</math>	+
-	i.e. we leave out the common factor	+
-	~~<math>~~2~~</math>~~, so that the fractions have the lowest common denominator	+
-	<math>2\~~centerdot~~ 2\~~centerdot~~ 3\~~centerdot~~ 7</math>,	+
-		+

-	<math>\frac{1}{12}-\frac{1}{14}=\frac{1}{2\~~centerdot~~ 2\~~centerdot~~ 3}-\frac{1}{2\~~centerdot~~ 7}=\frac{1}{2\~~centerdot~~ 2\~~centerdot~~ 3}\~~centerdot~~ \frac{7}{7}-\frac{1}{2\~~centerdot~~ 7}\~~centerdot~~ \frac{2\~~centerdot~~ 3}{2\~~centerdot~~ 3}</math>	+	{{Displayed math\|\|<math>\begin{align}
		+	\frac{1}{12}-\frac{1}{14} &= \frac{1}{2\cdot 2\cdot 3}-\frac{1}{2\cdot 7}\\[5pt]
		+	&= \frac{1}{2\cdot 2\cdot 3}\cdot \frac{7}{7}-\frac{1}{2\cdot 7}\cdot \frac{2\cdot 3}{2\cdot 3}\\[5pt]
		+	&= \frac{7}{2\cdot 2\cdot 3\cdot 7} - \frac{2\cdot 3}{2\cdot 2\cdot 3\cdot 7}\\[5pt]
		+	&= \frac{7}{84} - \frac{6}{84}\,\textrm{.}
		+	\end{align}</math>}}

-	The lowest common denominator is	+	The lowest common denominator is 84.
-	~~<math>~~84~~</math>~~.	+

Ian at 09:39, 22 September 2008

Ian — Mon, 22 Sep 2008 09:39:11 GMT

←Older revision		Revision as of 09:39, 22 September 2008
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-	{{~~NAVCONTENT_START~~}}	+	We divide up the two numerators into the smallest possible integer factors,
-	<~~center~~> ~~[[Image:1_2_2c~~.~~gif]]~~ </~~center~~>	+
-	{{~~NAVCONTENT_STOP~~}}	+
		+	<math>\begin{align}
		+	& 12=2\centerdot 6=2\centerdot 2\centerdot 3 \\
		+	& 14=2\centerdot 7 \\
		+	\end{align}</math>
		+
		+	The expression can thus be written as
		+
		+
		+	<math>\frac{1}{2\centerdot 2\centerdot 3}-\frac{1}{2\centerdot 7}</math>
		+
		+	Here, we see that the denominators have a factor
		+	<math>2</math>
		+	in common. We multiply the top and bottom of the first fraction by
		+	<math>7</math>
		+	and the second by
		+	<math>2\centerdot 3</math>
		+	i.e. we leave out the common factor
		+	<math>2</math>, so that the fractions have the lowest common denominator
		+	<math>2\centerdot 2\centerdot 3\centerdot 7</math>,
		+
		+
		+	<math>\frac{1}{12}-\frac{1}{14}=\frac{1}{2\centerdot 2\centerdot 3}-\frac{1}{2\centerdot 7}=\frac{1}{2\centerdot 2\centerdot 3}\centerdot \frac{7}{7}-\frac{1}{2\centerdot 7}\centerdot \frac{2\centerdot 3}{2\centerdot 3}</math>
		+
		+	The lowest common denominator is
		+	<math>84</math>.

Tekbot: Lösning 1.2:2c moved to Solution 1.2:2c: Robot: moved page

Tekbot — Tue, 09 Sep 2008 08:17:03 GMT

Lösning 1.2:2c moved to Solution 1.2:2c: Robot: moved page

←Older revision

Revision as of 08:17, 9 September 2008

Tekbot: Robot: Automated text replacement (-[[Bild: +[[Image:)

Tekbot — Thu, 21 Aug 2008 06:25:39 GMT

Robot: Automated text replacement (-[[Bild: +[[Image:)

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Lina — Wed, 26 Mar 2008 09:59:09 GMT

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