Solution 1.2:1d - Revision history

Tek at 07:36, 19 September 2008

Tek — Fri, 19 Sep 2008 07:36:52 GMT

←Older revision		Revision as of 07:36, 19 September 2008
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	When we have three fractions involved in an addition, we need to multiply the top and bottom of each fraction by the product of the other fraction's denominators so that all fractions have a common denominator,		When we have three fractions involved in an addition, we need to multiply the top and bottom of each fraction by the product of the other fraction's denominators so that all fractions have a common denominator,

-	~~<center>~~<math>\frac{1\~~centerdot~~ 4\~~centerdot~~ 5}{3\~~centerdot~~ 4\~~centerdot~~ 5}+\frac{1\~~centerdot~~ 3\~~centerdot~~ 5}{4\~~centerdot~~ 3\~~centerdot~~ 5}+\frac{1\~~centerdot~~ 3\~~centerdot~~ 4}{5\~~centerdot~~ 3\~~centerdot~~ 4}=\frac{20}{60}+\frac{15}{60}+\frac{12}{60}</math>~~</center>~~	+	{{Displayed math\|\|<math>\frac{1\cdot 4\cdot 5}{3\cdot 4\cdot 5}+\frac{1\cdot 3\cdot 5}{4\cdot 3\cdot 5}+\frac{1\cdot 3\cdot 4}{5\cdot 3\cdot 4}=\frac{20}{60}+\frac{15}{60}+\frac{12}{60}\,</math>.}}

	When all three fractions have a common denominator, they can easily be added up		When all three fractions have a common denominator, they can easily be added up

-	~~<center>~~<math>\frac{20}{60}+\frac{15}{60}+\frac{12}{60}=\frac{20+15+12}{60}=\frac{47}{60}</math>~~</center>~~	+	{{Displayed math\|\|<math>\frac{20}{60}+\frac{15}{60}+\frac{12}{60}=\frac{20+15+12}{60}=\frac{47}{60}\,</math>.}}

Ian — Thu, 11 Sep 2008 12:08:58 GMT

←Older revision		Revision as of 12:08, 11 September 2008
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	When we have three fractions involved in an addition, we need to multiply the top and bottom of each fraction by the product of the other fraction's denominators so that all fractions have a common denominator,		When we have three fractions involved in an addition, we need to multiply the top and bottom of each fraction by the product of the other fraction's denominators so that all fractions have a common denominator,

-		+	<center><math>\frac{1\centerdot 4\centerdot 5}{3\centerdot 4\centerdot 5}+\frac{1\centerdot 3\centerdot 5}{4\centerdot 3\centerdot 5}+\frac{1\centerdot 3\centerdot 4}{5\centerdot 3\centerdot 4}=\frac{20}{60}+\frac{15}{60}+\frac{12}{60}</math></center>
-	<math>\frac{1\centerdot 4\centerdot 5}{3\centerdot 4\centerdot 5}+\frac{1\centerdot 3\centerdot 5}{4\centerdot 3\centerdot 5}+\frac{1\centerdot 3\centerdot 4}{5\centerdot 3\centerdot 4}=\frac{20}{60}+\frac{15}{60}+\frac{12}{60}</math>	+

	When all three fractions have a common denominator, they can easily be added up		When all three fractions have a common denominator, they can easily be added up

-		+	<center><math>\frac{20}{60}+\frac{15}{60}+\frac{12}{60}=\frac{20+15+12}{60}=\frac{47}{60}</math></center>
-	<math>\frac{20}{60}+\frac{15}{60}+\frac{12}{60}=\frac{20+15+12}{60}=\frac{47}{60}</math>	+

Ian — Thu, 11 Sep 2008 12:05:49 GMT

←Older revision		Revision as of 12:05, 11 September 2008
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-	{{~~NAVCONTENT_START~~}}	+	When we have three fractions involved in an addition, we need to multiply the top and bottom of each fraction by the product of the other fraction's denominators so that all fractions have a common denominator,
-	~~<center> [[Image:1_2_1d.gif]]~~ </~~center~~>	+
-	{{~~NAVCONTENT_STOP~~}}	+
		+	<math>\frac{1\centerdot 4\centerdot 5}{3\centerdot 4\centerdot 5}+\frac{1\centerdot 3\centerdot 5}{4\centerdot 3\centerdot 5}+\frac{1\centerdot 3\centerdot 4}{5\centerdot 3\centerdot 4}=\frac{20}{60}+\frac{15}{60}+\frac{12}{60}</math>
		+
		+	When all three fractions have a common denominator, they can easily be added up
		+
		+
		+	<math>\frac{20}{60}+\frac{15}{60}+\frac{12}{60}=\frac{20+15+12}{60}=\frac{47}{60}</math>

Tekbot — Tue, 09 Sep 2008 08:15:43 GMT

←Older revision

Revision as of 08:15, 9 September 2008

Tekbot — Thu, 21 Aug 2008 06:24:29 GMT

Robot: Automated text replacement (-[[Bild: +[[Image:)

Lina — Wed, 26 Mar 2008 09:49:29 GMT

Ny sida: {{NAVCONTENT_START}} <center> Bild:1_2_1d.gif </center> {{NAVCONTENT_STOP}}

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