Solution 4.2:5c - Revision history

Tek at 11:11, 9 October 2008

2008-10-09T11:11:05Z

←Older revision		Revision as of 11:11, 9 October 2008
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-	If we express the angle	+	If we express the angle 330° in radians, we obtain
-	~~<math>\text{33}0^{\circ }</math>~~	+
-	in radians, we obtain	+

		+	{{Displayed math\|\|<math>330^{\circ} = 330^{\circ}\cdot \frac{\pi}{180^{\circ}}\ \text{radians} = \frac{11\pi}{6}\ \text{radians}</math>}}

-	~~<math>\text{33}0^{\circ }=\text{33}0^{\circ }\centerdot \frac{\pi }{180^{\circ }}</math>~~	+	and from exercise 3.3:1g, we know that
-	~~radians~~	+
-	~~<math>=\frac{11\pi }{6}</math>~~	+
-	~~radians~~	+

-	~~and from exercise 3.3:1g, we know that~~	+	{{Displayed math\|\|<math>\cos 330^{\circ} = \cos \frac{11\pi}{6} = \frac{\sqrt{3}}{2}\,\textrm{.}</math>}}
-		+
-		+
-	<math>\cos 330^{\circ }=\cos \frac{11\pi }{6}=\frac{\sqrt{3}}{2}</math>.	+

2008-09-29T08:09:21Z

←Older revision		Revision as of 08:09, 29 September 2008
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-	{{~~NAVCONTENT_START~~}}	+	If we express the angle
-	<~~center~~> ~~[[Image:4_2_5c.gif]]~~ </~~center~~>	+	<math>\text{33}0^{\circ }</math>
-	{{~~NAVCONTENT_STOP~~}}	+	in radians, we obtain
		+
		+
		+	<math>\text{33}0^{\circ }=\text{33}0^{\circ }\centerdot \frac{\pi }{180^{\circ }}</math>
		+	radians
		+	<math>=\frac{11\pi }{6}</math>
		+	radians
		+
		+	and from exercise 3.3:1g, we know that
		+
		+
		+	<math>\cos 330^{\circ }=\cos \frac{11\pi }{6}=\frac{\sqrt{3}}{2}</math>.

2008-09-09T09:48:23Z

←Older revision

Revision as of 09:48, 9 September 2008

2008-08-21T07:11:19Z

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2008-04-03T08:05:38Z

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