Solution 4.2:4d - Revision history

Tek at 10:37, 9 October 2008

2008-10-09T10:37:15Z

←Older revision		Revision as of 10:37, 9 October 2008
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-	If we use the unit circle and mark on the angle	+	If we use the unit circle and mark on the angle <math>\pi</math>, we see immediately that <math>\cos \pi = -1</math> and <math>\sin \pi = 0\,</math>.
-	<math>\pi </math>, we see immediately that	+
-	<math>\~~text{~~cos }\pi ~~\text{ }~~=-~~\text{~~1 }</math>	+
-	and	+
-	<math>\~~text{~~sin }\pi ~~\text{ }~~=0</math>.	+

	[[Image:4_2_4_d.gif\|center]]		[[Image:4_2_4_d.gif\|center]]
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	Thus,		Thus,

-		+	{{Displayed math\|\|<math>\tan \pi =\frac{\sin \pi }{\cos \pi }=\frac{0}{-1}=0\,\textrm{.}</math>}}
-	<math>\tan \pi =\frac{\sin \pi }{\cos \pi }=\frac{0}{-1}=0</math>	+

2008-09-28T13:15:01Z

←Older revision		Revision as of 13:15, 28 September 2008
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-	~~{{NAVCONTENT_START}}~~	+	If we use the unit circle and mark on the angle
-	<~~center~~> ~~[[Image:4_2_4d.gif]]~~ </~~center~~>	+	<math>\pi </math>, we see immediately that
-	{{~~NAVCONTENT_STOP~~}}	+	<math>\text{cos }\pi \text{ }=-\text{1 }</math>
		+	and
		+	<math>\text{sin }\pi \text{ }=0</math>.
		+
	[[Image:4_2_4_d.gif\|center]]		[[Image:4_2_4_d.gif\|center]]
		+
		+	Thus,
		+
		+
		+	<math>\tan \pi =\frac{\sin \pi }{\cos \pi }=\frac{0}{-1}=0</math>

2008-09-09T09:46:43Z

←Older revision

Revision as of 09:46, 9 September 2008

2008-08-21T07:10:29Z

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2008-08-15T15:11:49Z

2008-08-15T15:11:17Z

2008-04-03T08:01:25Z

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