Solution 4.2:3d - Revision history

Tek at 07:57, 9 October 2008

2008-10-09T07:57:34Z

←Older revision		Revision as of 07:57, 9 October 2008
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-	In order to get an angle between	+	In order to get an angle between <math>0</math> and <math>\text{2}\pi</math>, we subtract <math>2\pi</math> from <math>{7\pi }/{2}\,</math>, which also leaves the cosine value unchanged
-	<math>0</math>	+
-	and	+
-	<math>\text{2}\pi </math>, we subtract	+
-	<math>~~\text{~~2}\pi </math>	+
-	from	+
-	<math>{7\pi }/{2}\;</math>	+
-	, which also leaves the cosine value unchanged	+
-		+
-		+
-	~~<math>\cos \frac{7\pi }{2}=\cos \left( \frac{7\pi }{2}-2\pi \right)=\cos \frac{3\pi }{2}</math>~~	+
-		+
-		+
-	~~When we draw a line which makes an angle~~	+
-	~~<math>{3\pi }/{2}\;</math>~~	+
-	~~with the positive~~	+
-	~~<math>x</math>~~	+
-	~~-axis, we get the negative~~	+
-	~~<math>y</math>~~	+
-	~~-axis and we see that this line cuts the unit circle at the point~~	+
-	~~<math>\left( 0 \right.,\left. -1 \right)</math>. The~~	+
-	~~<math>x</math>~~	+
-	~~-coordinate of the intersection point is thus~~	+
-	~~<math>0</math>~~	+
-	~~and hence~~	+
-	~~<math>\cos {7\pi }/{2}\;=\cos {3\pi }/{2}\;=0</math>~~	+

		+	{{Displayed math\|\|<math>\cos\frac{7\pi}{2} = \cos\Bigl(\frac{7\pi}{2}-2\pi\Bigr) = \cos\frac{3\pi}{2}\,\textrm{.}</math>}}

		+	When we draw a line which makes an angle <math>3\pi/2</math> with the positive ''x''-axis, we get the negative ''y''-axis and we see that this line cuts the unit circle at the point (0,-1). The ''x''-coordinate of the intersection point is thus
		+	<math>0</math> and hence <math>\cos (7\pi/2) = \cos (3\pi/2) = 0\,</math>.

	[[Image:4_2_3_d.gif\|center]]		[[Image:4_2_3_d.gif\|center]]

Ian at 12:06, 28 September 2008

2008-09-28T12:06:44Z

←Older revision		Revision as of 12:06, 28 September 2008
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-	{{~~NAVCONTENT_START~~}}	+	In order to get an angle between
-	<~~center~~> ~~[[Image:4_2_3d~~.~~gif]]~~ </~~center~~>	+	<math>0</math>
-	{{~~NAVCONTENT_STOP~~}}	+	and
		+	<math>\text{2}\pi </math>, we subtract
		+	<math>\text{2}\pi </math>
		+	from
		+	<math>{7\pi }/{2}\;</math>
		+	, which also leaves the cosine value unchanged
		+
		+
		+	<math>\cos \frac{7\pi }{2}=\cos \left( \frac{7\pi }{2}-2\pi \right)=\cos \frac{3\pi }{2}</math>
		+
		+
		+	When we draw a line which makes an angle
		+	<math>{3\pi }/{2}\;</math>
		+	with the positive
		+	<math>x</math>
		+	-axis, we get the negative
		+	<math>y</math>
		+	-axis and we see that this line cuts the unit circle at the point
		+	<math>\left( 0 \right.,\left. -1 \right)</math>. The
		+	<math>x</math>
		+	-coordinate of the intersection point is thus
		+	<math>0</math>
		+	and hence
		+	<math>\cos {7\pi }/{2}\;=\cos {3\pi }/{2}\;=0</math>
		+
		+
		+
	[[Image:4_2_3_d.gif\|center]]		[[Image:4_2_3_d.gif\|center]]

Tekbot: Lösning 4.2:3d moved to Solution 4.2:3d: Robot: moved page

2008-09-09T09:44:43Z

Lösning 4.2:3d moved to Solution 4.2:3d: Robot: moved page

←Older revision

Revision as of 09:44, 9 September 2008

Tekbot: Robot: Automated text replacement (-[[Bild: +[[Image:)

2008-08-21T07:09:29Z

Robot: Automated text replacement (-[[Bild: +[[Image:)

←Older revision		Revision as of 07:09, 21 August 2008
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-	[[~~Bild~~:4_2_3_d.gif\|center]]	+	[[Image:4_2_3_d.gif\|center]]

Madde at 14:29, 15 August 2008

2008-08-15T14:29:46Z

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Oskar: Ny sida: {{NAVCONTENT_START}} Bild:4_2_3d.gif {{NAVCONTENT_STOP}}

2008-04-03T07:54:50Z

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