Solution 4.1:9 - Revision history

Tek at 11:50, 8 October 2008

2008-10-08T11:50:11Z

←Older revision		Revision as of 11:50, 8 October 2008
Line 1:		Line 1:
-	~~<math>\text{1}0</math>~~	+	10 seconds corresponds to 1/6 minutes, so that during that time period, the second hand sweeps over 1/6 of a turn, i.e. the sector of a circle with angle
-	seconds corresponds to	+
-	~~<math>\frac{~~1}{6~~}</math>~~	+
-	minutes, so that during that time period, the second hand sweeps over	+
-	~~<math>\frac{~~1~~}{6}<~~/~~math>~~	+
-	of a turn, i.e. the sector of a circle with angle	+

		+	{{Displayed math\|\|<math>\alpha = \frac{1}{6}\cdot 2\pi\ \text{radians} = \frac{\pi}{3}\ \text{radians.}</math>}}

-	<math>\alpha =\frac{1}{6}\centerdot 2\pi </math>
-	radians
-	<math>=\frac{\pi }{3}</math>
-	radians
-
-
-	{{NAVCONTENT_START}}
	<center> [[Image:4_1_9_.gif]] </center>		<center> [[Image:4_1_9_.gif]] </center>
-
-
-	{{NAVCONTENT_STOP}}

	The area of the sector is		The area of the sector is

-	~~Area~~	+	{{Displayed math\|\|<math>\text{Area} = \frac{1}{2}\alpha r^{2} = \frac{1}{2}\cdot \frac{\pi}{3}\cdot (8\ \text{cm})^2 = \frac{32\pi}{3}\ \text{cm}^{2} \approx 33\textrm{.}5\ \text{cm}^{2}\,\textrm{.}</math>}}
-	<math>=\frac{1}{2}\alpha r^{2}=\frac{1}{2}\~~centerdot~~ \frac{\pi }{3}\~~centerdot \left~~( 8\ \text{cm} ~~\right~~)^{2}=\frac{32\pi }{3}\ \text{cm}^{2}\approx 33.5\ \text{cm}^{2}</math>	+

2008-09-27T12:30:05Z

←Older revision		Revision as of 12:30, 27 September 2008
Line 1:		Line 1:
		+	<math>\text{1}0</math>
		+	seconds corresponds to
		+	<math>\frac{1}{6}</math>
		+	minutes, so that during that time period, the second hand sweeps over
		+	<math>\frac{1}{6}</math>
		+	of a turn, i.e. the sector of a circle with angle
		+
		+
		+	<math>\alpha =\frac{1}{6}\centerdot 2\pi </math>
		+	radians
		+	<math>=\frac{\pi }{3}</math>
		+	radians
		+
		+
	{{NAVCONTENT_START}}		{{NAVCONTENT_START}}
	<center> [[Image:4_1_9_.gif]] </center>		<center> [[Image:4_1_9_.gif]] </center>

-	~~<center> [[Image:4_1_9.gif]] </center>~~	+
	{{NAVCONTENT_STOP}}		{{NAVCONTENT_STOP}}
		+
		+	The area of the sector is
		+
		+	Area
		+	<math>=\frac{1}{2}\alpha r^{2}=\frac{1}{2}\centerdot \frac{\pi }{3}\centerdot \left( 8\ \text{cm} \right)^{2}=\frac{32\pi }{3}\ \text{cm}^{2}\approx 33.5\ \text{cm}^{2}</math>

2008-09-09T09:39:23Z

Lösning 4.1:9 moved to Solution 4.1:9: Robot: moved page

←Older revision

Revision as of 09:39, 9 September 2008

2008-08-21T07:06:49Z

Robot: Automated text replacement (-[[Bild: +[[Image:)

2008-08-15T14:39:49Z

2008-04-02T13:33:59Z

Ny sida: {{NAVCONTENT_START}} <center> Bild:4_1_9.gif </center> {{NAVCONTENT_STOP}}

New page

{{NAVCONTENT_START}}
<center> [[Bild:4_1_9.gif]] </center>
{{NAVCONTENT_STOP}}