Solution 4.1:3c - Revision history

Tek at 10:21, 3 October 2008

2008-10-03T10:21:40Z

←Older revision		Revision as of 10:21, 3 October 2008
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-	In this right-angled triangle, the side of length	+	In this right-angled triangle, the side of length 17 is the hypotenuse (it is the side which is opposite the right angle). The Pythagorean theorem then gives
-	~~<math>\text{~~17~~}</math>~~	+
-	is the hypotenuse (it is the side which is opposite the right angle). ~~Pythagoras'~~ theorem then gives	+
-		+
-		+
-	~~<math>\text{17}^{2}=8^{2}+x^{2}</math>~~	+

		+	{{Displayed math\|\|<math>17^2 = 8^2 + x^2</math>}}

	or		or

-		+	{{Displayed math\|\|<math>x^2 = 17^2 - 8^2\,\textrm{.}</math>}}
-	<math>x^{2}=~~\text{~~17}^{2}-8^{2}</math>	+
-		+

	We get		We get

-		+	{{Displayed math\|\|<math>\begin{align}
-	<math>\begin{align}	+	x &= \sqrt{17^2-8^2} = \sqrt{289-64} = \sqrt{225}\\[5pt]
-	& x=\sqrt~~{\text~~{17}^{2}-8^{2}}=\sqrt{289-64}=\sqrt{225} \\	+	&= \sqrt{9\cdot 25} = \sqrt{3^2\cdot 5^2} = 3\cdot 5 = 15\,\textrm{.}
-	& =\sqrt{9\~~centerdot~~ 25}=\sqrt{3^{2}\~~centerdot~~ 5^{2}}=3\~~centerdot~~ 5=15. \\	+	\end{align}</math>}}
-	\end{align}</math>	+

2008-09-27T09:36:26Z

←Older revision		Revision as of 09:36, 27 September 2008
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-	{{~~NAVCONTENT_START~~}}	+	In this right-angled triangle, the side of length
-	<~~center~~> ~~[[Image:4_1_3c.gif]]~~ </~~center~~>	+	<math>\text{17}</math>
-	{{~~NAVCONTENT_STOP~~}}	+	is the hypotenuse (it is the side which is opposite the right angle). Pythagoras' theorem then gives
		+
		+
		+	<math>\text{17}^{2}=8^{2}+x^{2}</math>
		+
		+
		+	or
		+
		+
		+	<math>x^{2}=\text{17}^{2}-8^{2}</math>
		+
		+
		+	We get
		+
		+
		+	<math>\begin{align}
		+	& x=\sqrt{\text{17}^{2}-8^{2}}=\sqrt{289-64}=\sqrt{225} \\
		+	& =\sqrt{9\centerdot 25}=\sqrt{3^{2}\centerdot 5^{2}}=3\centerdot 5=15. \\
		+	\end{align}</math>

2008-09-09T09:34:43Z

←Older revision

Revision as of 09:34, 9 September 2008

2008-08-21T07:04:29Z

Robot: Automated text replacement (-[[Bild: +[[Image:)

2008-04-02T12:56:34Z

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