Solution 3.3:2a - Revision history

Tek at 14:25, 1 October 2008

2008-10-01T14:25:19Z

←Older revision		Revision as of 14:25, 1 October 2008
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-	The logarithm	+	The logarithm <math>\mathop{\text{lg}} 0\textrm{.}1</math> is defined as that number which should stand in the coloured box in order that the equality
-	<math>\text{lg }0.\~~text~~{1 }</math>	+
-	is defined as that number which should stand in the ~~(??) grey~~ box in order that the equality	+
-		+
-		+
-	~~<math>10^{??}=0.1</math>~~	+

		+	{{Displayed math\|\|<math>10^{\bbox[#FFEEAA;,1.5pt]{\phantom{\scriptstyle ??}}} = 0\textrm{.}1</math>}}

	should hold. In this case, we see that		should hold. In this case, we see that

		+	{{Displayed math\|\|<math>10^{-1} = 0\textrm{.}1</math>}}

-	~~<math>10^{-1}=0.1</math>~~	+	and therefore <math>\mathop{\text{lg}} 0\textrm{.}1 = -1\,</math>.
-		+
-		+
-	and therefore	+
-	<math>\text{lg }0.\~~text~~{1}=-\~~text{1}~~</math>.	+

2008-09-25T13:05:45Z

←Older revision		Revision as of 13:05, 25 September 2008
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-	{{~~NAVCONTENT_START~~}}	+	The logarithm
-	<~~center~~> ~~[[Image:3_3_2a~~.~~gif]]~~ </~~center~~>	+	<math>\text{lg }0.\text{1 }</math>
-	{{~~NAVCONTENT_STOP~~}}	+	is defined as that number which should stand in the (??) grey box in order that the equality
		+
		+
		+	<math>10^{??}=0.1</math>
		+
		+
		+	should hold. In this case, we see that
		+
		+
		+	<math>10^{-1}=0.1</math>
		+
		+
		+	and therefore
		+	<math>\text{lg }0.\text{1}=-\text{1}</math>.

2008-09-09T09:20:43Z

←Older revision

Revision as of 09:20, 9 September 2008

2008-08-21T06:57:29Z

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2008-04-02T09:22:37Z

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