Solution 3.1:4b - Revision history

Tek at 10:54, 30 September 2008

2008-09-30T10:54:16Z

←Older revision		Revision as of 10:54, 30 September 2008
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-	By writing	+	By writing <math>0\textrm{.}027</math> as <math>27\cdot 10^{-3}</math>, where
-	<math>0.0\~~text~~{27 }</math>	+	<math>27 = 3\cdot 3\cdot 3 = 3^3</math> and <math>10^{-3} = (10^{-1})^{3} = 0\textrm{.}1^3</math> we see that
-	as	+
-	<math>~~\text{~~27}\cdot ~~\text{1}0~~^{-~~\text{~~3}}</math>, where	+
-	<math>~~\text{~~27}=~~\text{~~3}\cdot ~~\text{~~3}\cdot ~~\text{~~3}=~~\text{~~3}^~~{\text{~~3}}</math>	+
-	and	+
-	<math>10^{-3}=~~\left~~( 10^{-1} ~~\right~~)^{3}=0.1^{3}</math>	+
-	we see that	+

		+	{{Displayed math\|\|<math>\begin{align}
		+	\sqrt[3]{0\textrm{.}027} &= \sqrt[3]{27\cdot 10^{-3}} = \sqrt[3]{27}\cdot\sqrt[3]{10^{-3}} = \sqrt[3]{3^{3}}\cdot\sqrt[3]{0\textrm{.}1^3}\\[5pt]
		+	&= 3\cdot 0\textrm{.}1 = 0\textrm{.}3\,\textrm{,}
		+	\end{align}</math>}}

-	~~<math>\begin{align}~~	+	where we have used <math>\sqrt[3]{a^{3}} = \bigl(a^{3}\bigr)^{1/3} = a^{3\cdot \frac{1}{3}} = a^{1} = a\,\textrm{.}</math>
-	~~& \sqrt[3]{0.027}=\sqrt[3]{27\centerdot 10^{-3}}=\sqrt[3]{27}\centerdot \sqrt[3]{10^{-3}}=\sqrt[3]{3^{3}}\centerdot \sqrt[3]{0.1^{3}} \\~~	+
-	~~& =3\centerdot 0.1=0.3 \\~~	+
-	~~\end{align}</math>~~	+
-		+
-		+
-	where we have used	+
-	<math>\sqrt[3]{a^{3}}=\~~left~~( a^{3} \~~right~~)^~~{\frac~~{1}{3}}=a^{3\~~centerdot~~ \frac{1}{3}}=a^{1}=a</math>	+

2008-09-22T13:58:46Z

←Older revision		Revision as of 13:58, 22 September 2008
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-	{{~~NAVCONTENT_START~~}}	+	By writing
-	<~~center~~> [~~[Image:3_1_4b~~.~~gif~~]] </~~center~~>	+	<math>0.0\text{27 }</math>
-	{{~~NAVCONTENT_STOP~~}}	+	as
		+	<math>\text{27}\cdot \text{1}0^{-\text{3}}</math>, where
		+	<math>\text{27}=\text{3}\cdot \text{3}\cdot \text{3}=\text{3}^{\text{3}}</math>
		+	and
		+	<math>10^{-3}=\left( 10^{-1} \right)^{3}=0.1^{3}</math>
		+	we see that
		+
		+
		+	<math>\begin{align}
		+	& \sqrt[3]{0.027}=\sqrt[3]{27\centerdot 10^{-3}}=\sqrt[3]{27}\centerdot \sqrt[3]{10^{-3}}=\sqrt[3]{3^{3}}\centerdot \sqrt[3]{0.1^{3}} \\
		+	& =3\centerdot 0.1=0.3 \\
		+	\end{align}</math>
		+
		+
		+	where we have used
		+	<math>\sqrt[3]{a^{3}}=\left( a^{3} \right)^{\frac{1}{3}}=a^{3\centerdot \frac{1}{3}}=a^{1}=a</math>

2008-09-09T09:11:23Z

←Older revision

Revision as of 09:11, 9 September 2008

2008-08-21T06:52:49Z

Robot: Automated text replacement (-[[Bild: +[[Image:)

2008-04-01T14:03:49Z

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